PostgreSQL命令：使用从第一个查询获得的结果并在第二个查询中使用它：写为单个查询

Question

SELECT partner_id 
FROM trip_delivery_sales ts 
WHERE ts.route_id='152' 
GROUP BY ts.partner_id

从查询中我们可以得到合作伙伴 id。使用该合作伙伴 id，我们要检查 trip delicery 销售行表并希望找到每个客户最近两次销售的产品数量总和。如果最后两次销售的产品数量为 2 和 5，则希望结果为 partner_id |算为Mn2333 - 7

例如，我将合作伙伴 ID 设为 34806。但我想检查从上次查询中获得的所有合作伙伴 ID

SELECT product_qty 
FROM trip_delivery_sales_lines td 
WHERE td.partner_id='34806' 
  AND td.route_id='152' 
  AND td.product_id='432' 
ORDER BY td.order_date DESC 
LIMIT 2

Answer 1

您可以运行此查询

SELECT td.partner_id,sum(product_qty) 
FROM trip_delivery_sales_lines td,
(SELECT partner_id FROM trip_delivery_sales ts WHERE ts.route_id='152') as ts
WHERE td.partner_id=ts.partner_id
AND td.product_id='432' 
GROUP BY td.partner_id
ORDER BY td.order_date DESC 
LIMIT 2

或者这个

with ts as (SELECT distinct partner_id FROM trip_delivery_sales WHERE route_id='152')
SELECT td.partner_id,sum(product_qty)
FROM trip_delivery_sales_lines td,ts
WHERE td.partner_id=ts.partner_id
AND td.product_id='432' 
GROUP BY td.partner_id
ORDER BY td.order_date DESC 
LIMIT 2

Answer 2

您可能正在寻找

SELECT DISTINCT ts.partner_id, ARRAY(
  SELECT product_qty
  FROM trip_delivery_sales_lines td 
  WHERE td.partner_id=ts.partner_id
    AND td.product_id='432' 
  ORDER BY td.order_date DESC 
  LIMIT 2
) AS product_qty_arr
FROM trip_delivery_sales ts 
WHERE ts.route_id='152'

或者只是

SELECT
  partner_id,
  array_agg(product_qty ORDER BY order_date DESC) as product_qty_arr
FROM (
  SELECT
    td.partner_id,
    td.product_qty,
    td.order_date,
    row_number() OVER (PARTITION BY td.partner_id ORDER BY td.order_date DESC)
  FROM trip_delivery_sales_lines td
  JOIN trip_delivery_sales ts USING (partner_id)
  WHERE ts.route_id='152'  
    AND td.product_id='432'
) AS enumerated
WHERE row_number <= 2
GROUP BY partner_id

另请参阅PostgreSQL: top n entries per item in same table 或 Optimize GROUP BY query to retrieve latest row per user