【发布时间】:2015-10-28 11:14:28
【问题描述】:
我有以下型号:
月球 -> 行星 -> 恒星 -> 银河 -> 宇宙
月亮belongs_to行星,行星belongs_to星星等等:
class Moon < ActiveRecord::Base
belongs_to :planet, inverse_of: :moons
has_one :star, through: :planet
has_one :galaxy, through: :star
has_one :universe, through: :galaxy
end
class Planet < ActiveRecord::Base
belongs_to :star, inverse_of: :planets
has_many :moons, inverse_of: :planet, dependent: :destroy
end
问题
我试图让 Rails 将这些对象的层次结构加载到内存中。我正在努力实现两件事:
- 使用一个高效的查询加载所有内容
- 无需额外调用数据库即可使用
moon.galaxy而不是moon.planet.star.galaxy等调用。
我尝试了两种方法。第一个(m1)在Moon 上调用includes,所有关系都变平了。这导致查询效率非常低,但我可以调用m1.galaxy。第二个 (m2) 使用关系层次结构调用 includes。这会产生高效的查询,但我可以调用m2.galaxy 而无需访问数据库。
这样做的正确方法是什么?
示例
m1 - 低效查询,m2 - 高效查询
irb(main):152:0* m1 = Moon.includes(:planet, :star, :galaxy).where(galaxies: {name: 'The Milky Way'}).first
SQL (1.9ms) SELECT "moons"."id" AS t0_r0, "moons"."name" AS t0_r1, "moons"."planet_id" AS t0_r2, "moons"."created_at" AS t0_r3, "moons"."updated_at" AS t0_r4, "planets"."id" AS t1_r0, "planets"."name" AS t1_r1, "planets"."star_id" AS t1_r2, "planets"."created_at" AS t1_r3, "planets"."updated_at" AS t1_r4, "stars"."id" AS t2_r0, "stars"."name" AS t2_r1, "stars"."galaxy_id" AS t2_r2, "stars"."created_at" AS t2_r3, "stars"."updated_at" AS t2_r4, "galaxies"."id" AS t3_r0, "galaxies"."name" AS t3_r1, "galaxies"."universe_id" AS t3_r2, "galaxies"."created_at" AS t3_r3, "galaxies"."updated_at" AS t3_r4 FROM "moons" LEFT OUTER JOIN "planets" ON "planets"."id" = "moons"."planet_id" LEFT OUTER JOIN "planets" "planets_moons_join" ON "planets_moons_join"."id" = "moons"."planet_id" LEFT OUTER JOIN "stars" ON "stars"."id" = "planets_moons_join"."star_id" LEFT OUTER JOIN "planets" "planets_moons_join_2" ON "planets_moons_join_2"."id" = "moons"."planet_id" LEFT OUTER JOIN "stars" "stars_moons_join" ON "stars_moons_join"."id" = "planets_moons_join_2"."star_id" LEFT OUTER JOIN "galaxies" ON "galaxies"."id" = "stars_moons_join"."galaxy_id" WHERE "galaxies"."name" = $1 ORDER BY "moons"."id" ASC LIMIT 1 [["name", "The Milky Way"]]
=> #<Moon id: 1, name: "The Moon", planet_id: 1, created_at: "2015-10-28 10:02:04", updated_at: "2015-10-28 10:02:04">
irb(main):153:0> m2 = Moon.includes(planet: {star: :galaxy}).where(galaxies: {name: 'The Milky Way'}).first
SQL (0.5ms) SELECT "moons"."id" AS t0_r0, "moons"."name" AS t0_r1, "moons"."planet_id" AS t0_r2, "moons"."created_at" AS t0_r3, "moons"."updated_at" AS t0_r4, "planets"."id" AS t1_r0, "planets"."name" AS t1_r1, "planets"."star_id" AS t1_r2, "planets"."created_at" AS t1_r3, "planets"."updated_at" AS t1_r4, "stars"."id" AS t2_r0, "stars"."name" AS t2_r1, "stars"."galaxy_id" AS t2_r2, "stars"."created_at" AS t2_r3, "stars"."updated_at" AS t2_r4, "galaxies"."id" AS t3_r0, "galaxies"."name" AS t3_r1, "galaxies"."universe_id" AS t3_r2, "galaxies"."created_at" AS t3_r3, "galaxies"."updated_at" AS t3_r4 FROM "moons" LEFT OUTER JOIN "planets" ON "planets"."id" = "moons"."planet_id" LEFT OUTER JOIN "stars" ON "stars"."id" = "planets"."star_id" LEFT OUTER JOIN "galaxies" ON "galaxies"."id" = "stars"."galaxy_id" WHERE "galaxies"."name" = $1 ORDER BY "moons"."id" ASC LIMIT 1 [["name", "The Milky Way"]]
=> #<Moon id: 1, name: "The Moon", planet_id: 1, created_at: "2015-10-28 10:02:04", updated_at: "2015-10-28 10:02:04">
m1 - 我可以在内存中调用moon.galaxy.name,m2 - moon.galaxy.name 调用DB
irb(main):154:0> m1.galaxy.name
=> "The Milky Way"
irb(main):155:0> m2.galaxy.name
Galaxy Load (0.5ms) SELECT "galaxies".* FROM "galaxies" INNER JOIN "stars" ON "galaxies"."id" = "stars"."galaxy_id" INNER JOIN "planets" ON "stars"."id" = "planets"."star_id" WHERE "planets"."id" = $1 LIMIT 1 [["id", 1]]
=> "The Milky Way"
m1 - moon.planet.star.galaxy.name 调用 DB,m2 - 我可以在内存中调用 moon.planet.star.galaxy.name
irb(main):156:0> m1.planet.star.galaxy.name
Star Load (3.3ms) SELECT "stars".* FROM "stars" WHERE "stars"."id" = $1 LIMIT 1 [["id", 1]]
Galaxy Load (0.3ms) SELECT "galaxies".* FROM "galaxies" WHERE "galaxies"."id" = $1 LIMIT 1 [["id", 1]]
=> "The Milky Way"
irb(main):157:0> m2.planet.star.galaxy.name
=> "The Milky Way"
查询的差异
【问题讨论】:
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关于急切加载,请考虑阅读在 Rails 中执行此操作的不同方法。有许多文章(有些比其他文章更新)详细,您应该能够在那里找到一些信息以提供帮助,例如,blog.bigbinary.com/2013/07/01/…
标签: sql ruby-on-rails postgresql ruby-on-rails-4 rails-activerecord