在 Oracle 中创建 CTE

Question

我正在尝试在Oracle 中创建一个CTE，它不会从现有表中进行选择，而是将数据插入其中。目前，我正在创建一个表，然后在 query 完成后将其删除。有没有办法创建一个有效地做同样事情的CTE？这是我当前的代码：

create table RTG_YEARS
(YR date);

insert into RTG_YEARS values (to_date('2013-01-01', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2013-12-31', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2014-01-01', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2014-12-31', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2015-01-01', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2015-12-31', 'yyyy-mm-dd'));

Answer 1

您可以通过从对偶中选择日期值并将它们合并在一起来创建公用表表达式（CTE、subquery factoring 等）：

with RTG_YEARS (YR) as (
  select to_date('2013-01-01', 'yyyy-mm-dd') from dual
  union all select to_date('2013-12-31', 'yyyy-mm-dd') from dual
  union all select to_date('2014-01-01', 'yyyy-mm-dd') from dual
  union all select to_date('2014-12-31', 'yyyy-mm-dd') from dual
  union all select to_date('2015-01-01', 'yyyy-mm-dd') from dual
  union all select to_date('2015-12-31', 'yyyy-mm-dd') from dual
)
select * from RTG_YEARS;

YR       
----------
2013-01-01
2013-12-31
2014-01-01
2014-12-31
2015-01-01
2015-12-31

与 CTE 无关，但您可以使用 date literals 减少打字次数：

with RTG_YEARS (YR) as (
  select date '2013-01-01' from dual
  union all select date '2013-12-31' from dual
  union all select date '2014-01-01' from dual
  union all select date '2014-12-31' from dual
  union all select date '2015-01-01' from dual
  union all select date '2015-12-31' from dual
)
select * from RTG_YEARS;