【发布时间】:2016-01-12 06:29:09
【问题描述】:
我在尝试创建数据库时遇到问题... 我想我在 android 中创建数据库的过程中做错了什么。 我也搜索了网页,但没有找到任何好的线索。 这是我的代码:
package com.example.raqib.database;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.os.Bundle;
import android.support.design.widget.FloatingActionButton;
import android.support.design.widget.Snackbar;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.Toolbar;
import android.util.Log;
import android.view.Gravity;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
public class MainActivity extends AppCompatActivity implements View.OnClickListener {
static EditText stName;
static EditText stRollNo;
static EditText stSem;
Button enterDB;
private Object context;
// creating database
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
getIntent();
FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
.setAction("Action", null).show();
}
});
}
public void enterDetails(View view) {
stName = (EditText) findViewById(R.id.stName);
stRollNo = (EditText) findViewById(R.id.stRollNo);
stSem = (EditText) findViewById(R.id.stSem);
enterDB = (Button) findViewById(R.id.enterDB);
enterDB.setOnClickListener(this);
}
public void onClick(View v){
String st_Name = stName.getText().toString();
int st_RollNo = Integer.parseInt(stRollNo.getText().toString());
String st_sem = stSem.getText().toString();
SQLiteDatabase db = openOrCreateDatabase("database", MODE_PRIVATE, null);
db.execSQL("create table if not exists student (name varchar, roll_no int(4), semester varchar);");
// db.execSQL("insert into student( name , roll_no , semester )" + "values"+" ('"+ st_Name + "'," + st_RollNo + ",'" +st_sem + "');");
ContentValues values = new ContentValues();
values.put("name", st_Name);
values.put("roll_no", st_RollNo); values.put("semester", st_sem); db.insert("student", null, values);
Cursor cursor = db.rawQuery("select * from student", null);
cursor.moveToFirst();
Log.e("Name : ", cursor.getString(cursor.getColumnIndex("name")));
Toast toast = Toast.makeText(MainActivity.this, " WOW! Successfully entered data in Database", Toast.LENGTH_LONG);
toast.setGravity(Gravity.CENTER,0, 0);
toast.show();
// student registeredData = new student(st_Name,st_RollNo,st_sem);
}
}
**我面临的错误是:它显示 st_Name 而不是这个语句的值:
Log.e("Name : ", cursor.getString(cursor.getColumnIndex("name")));
**
【问题讨论】:
-
添加单引号就可以了
-
在哪里加单引号亲爱的!!
-
刚刚@Jörn Buitink 承认了这一点
-
按照您的建议添加单引号会出现一个问题,那就是:它认为 st_Name 是一个字符串,而不是它的值......因为 st_Name 包含我在运行时通过 EditText 输入的字符串。 ..
标签: android sql database database-design rdbms