php - sql select“where”等于几个变量？

Question

我正在从 JSON 链接解析 3 个变量，每个变量都包含电影院的名称：

$cinema1
$cinema2
$cinema3

之后，我需要从表中选择所有 3 个电影院的 id，然后使用该 id 查找表“movietimings”以查看今天是否有电影正在播放，是否有电影正在播放今天电影院，然后我需要去“电影”表并显示有关该电影的所有信息。

所以，这就是已经完成的：

    $sql2 = "SELECT DISTINCT * FROM cinema WHERE cinemaname = '$cinema1' AND cinemaname='$cinema2' AND cinemaname='$cinema3' ";

    $result2 = $conn->query($sql2);

    if ($result2->num_rows > 0) {
        // output data of each row
        while($row2 = $result2->fetch_assoc()) {
$cinemaid2 = $row2['id'];// I have received a cinema id




//getting the main id, since the id I just got is a branch of the main cinema, so the main id that is associated with movie timings is down below
$sql5 = "SELECT DISTINCT * FROM cinemas WHERE cinemaname = '$cinemaid2'";

$result5 = $conn->query($sql5);

if ($result5->num_rows > 0) {
    // output data of each row
    while($row5 = $result5->fetch_assoc()) {

$cinemaid = $row5['id'];//received main id required

$today = date("m/d/Y");//getting todays date

//now trying to find if a movie today playing
$sql3 = "SELECT  * FROM moviecinemashowsassociation WHERE cinemaid LIKE '$cinemaid' AND showdate LIKE '$today'";

$result3 = $conn->query($sql3);

if ($result3->num_rows > 0) {
    // output data of each row
    while($row3 = $result3->fetch_assoc()) {
$movieid = $row3['movieid'];// selected a movie id played today

//selecting information about movie
$sql4 = "SELECT  * FROM movie WHERE id='$movieid'";

$result4 = $conn->query($sql4);

if ($result4->num_rows > 0) {
    // output data of each row
    while($row4 = $result4->fetch_assoc()) {

问题是我有 3 个不同的电影院，它们应该经过一个循环。

Answer 1

您正在寻找 OR 条件而不是 AND 条件，因为 cinemaname 不能在同一时间点保存多个值，因此它将是指定的值中的任何一个

WHERE cinemaname = '$cinema1' OR cinemaname = '$cinema2' OR cinemaname = '$cinema3'

（或）使用IN 运算符

WHERE cinemaname IN ('$cinema1' ,'$cinema2' , '$cinema3')