【发布时间】:2020-06-03 06:28:20
【问题描述】:
我有如下三张表。
submission1_header
Submission1_id Submission2_id Name
100 500 Rahul
200 500 Deva
submission1_details
Submission1_id Submission2_id Question_no Answer
100 500 1 YES
100 500 2 YES
100 500 3 NO
100 500 4 NO
100 500 5 YES
200 501 1 YES
200 501 3 YES
200 501 4 YES
submission2_details
Submission2_id Question_no Answer
500 1 YES
500 2 YES
501 1 YES
501 2 YES
501 3 NA
使用下面的查询我得到如下输出(仅连接前两个表)
==================DYNAMIC PIVOT===============
DECLARE
@columns NVARCHAR(MAX) = '',
@sql NVARCHAR(MAX) = '';
-- select the question num
SELECT
@columns+=QUOTENAME(Question_no) + ','
FROM
submission1_details WHERE Submission1_id=100
ORDER BY
Question_no;
-- remove the last comma
SET @columns = LEFT(@columns, LEN(@columns) - 1);
-- construct dynamic SQL
SET @sql ='
SELECT * FROM
(
SELECT Submission1_id,Name,Question_no,Answer FROM submission1_header t1 INNER JOIN submission1_details t2 ON t1.Submission1_id= t2.Submission1_id WHERE t1.Submission1_id=100
) t
PIVOT(
MAX(Answer)
for Question_no IN ('+ @columns +')
) AS pivot_table;';
-- execute the dynamic SQL
EXECUTE sp_executesql @sql;
输出:
Submission1_id NAME 1 2 3 4 5
100 Rahul YES YES NO NO YES
现在我也想加入第三张桌子。输出应该是:
Submission1_id NAME sub1_Q1 sub1_Q2 sub1_Q3 sub1_Q4 sub1_Q5 sub2_Q1 sub2_Q2 sub2_Q3
100 Rahul YES YES NO NO YES YES YES
如果 submission1_details 表最多包含 10 个问题,则输出应显示从 sub1_Q1 到 sub1_Q10 的列。
同样,如果 submission2_details 表最多包含 20 个问题,则输出应创建从 sub2_Q1 到 sub2_Q20 的列。
【问题讨论】:
标签: sql sql-server sql-server-2008 pivot dynamic-pivot