Laravel 原始 sql 查询

Question

select CONCAT(app_users.first_name) as display_name,COUNT(NewLeads.id)
from `app_users`
LEFT JOIN (SELECT app_leads.id, app_leads.owner_user_id from app_leads JOIN app_lead_version ON app_leads.id=app_lead_version.lead_id WHERE `app_leads`.`flag` = '1' and `app_leads`.`created_at` >= "2021-06-27 00:00:00" and `app_leads`.`created_at` <= "2021-06-28 23:59:59" ) as NewLeads ON NewLeads.owner_user_id=app_users.id
where `app_users`.`display_name` in ('Sam', 'Ash', 'Dan', 'Paul Thengilan', 'Scott')
group by `app_users`.`display_name`
order by `app_users`.`display_name` asc



$result = User::select(DB::raw('CONCAT(app_users.first_name) as display_name'),DB::raw('Count(app_leads.id) as new'))
            ->leftjoin('leads',function($join)use($time){
                $join->leftjoin('lead_version','lead_version.lead_id','=','leads.id');
                $join->on('leads.flag','=',DB::raw("'1'"));
                $join->on('leads.created_at','>=',DB::raw('"'.date("Y-m-d",strtotime($time)).' 00:00:00"'));
                $join->on('leads.created_at','<=',DB::raw('"'.date("Y-m-d",strtotime($time)).' 23:59:59"'));
                $join->on('leads.flag','=',DB::raw("'1'"));
                $join->on('leads.owner_user_id','=','users.id');

            })->whereIn('users.display_name',$user_display)->groupBy('users.display_name')->orderBy('users.display_name')->get()->toArray();

这是我的原始 sql 查询，我想将其转换为 laravel sql 查询下面是转换后的 laravel 查询，但是当我运行这两个查询时，我得到不同的结果，谁能帮我看看我的 laravel sql 查询出了什么问题

Answer 1

您可以调试这种情况的一种方法是删除

->get()->toArray()

来自$result 并记录/转储$result->toSql() 的值。

如果您可以将该输出添加到问题中，它可能会更容易为您提供帮助。