将行转换为更多列

Question

我有一个有 4 列的表格 ID,ROL_NUM,NAME,DEPT 并记录如下：

ID          ROL_NUM     NAME        DEPT
1           1           Rajasekar   CSE
1           1           Bala        CSE
1           1           Poo         IT
1           1           bhasker     CSE

我需要这个表的输出如下

ID          ROL_NUM             NAME                DEPT            NAME            DEPT            NAME            DEPT            NAME            DEPT
1           1                   Rajasekar           CSE             Bala            CSE             Poo             It              bhasker         CSE

有人提供建议或通过提供查询来帮助我。

Answer 1

您可以使用条件聚合进行此类旋转：

select ID, rol_num, max( case when rn = 1 then name end ) as name1,
                    max( case when rn = 1 then dept end ) as dept1,
                    max( case when rn = 2 then name end ) as name2,
                    max( case when rn = 2 then dept end ) as dept2,
                    max( case when rn = 3 then name end ) as name3,
                    max( case when rn = 3 then dept end ) as dept3,
                    max( case when rn = 4 then name end ) as name4,
                    max( case when rn = 4 then dept end ) as dept4                    
  from
  (
  select t.*, row_number() over (order by t.name) as rn
    from tab t
   order by t.name 
  )
  group by ID, rol_num  

Demo

Answer 2

SELECT
ID,
ROL_NUM,
REGEXP_SUBSTR(NAMEDEPT, '[^,]+', 1, 1) NAME,
REGEXP_SUBSTR(NAMEDEPT, '[^,]+', 1, 2) DEPT,
REGEXP_SUBSTR(NAMEDEPT, '[^,]+', 1, 3) NAME,
REGEXP_SUBSTR(NAMEDEPT, '[^,]+', 1, 4) DEPT,
REGEXP_SUBSTR(NAMEDEPT, '[^,]+', 1, 5) NAME,
REGEXP_SUBSTR(NAMEDEPT, '[^,]+', 1, 6) DEPT,
REGEXP_SUBSTR(NAMEDEPT, '[^,]+', 1, 7) NAME,
REGEXP_SUBSTR(NAMEDEPT, '[^,]+', 1, 8) DEPT
from (SELECT ID
      ,ROL_NUM
      ,LISTAGG(NAME || ',' ||DEPT,',') WITHIN GROUP (ORDER BY ID) AS NAMEDEPT
FROM TABLE1
GROUP BY ID,ROL_NUM);

输出

ID  ROL_NUM NAME    DEPT    NAME    DEPT    NAME        DEPT    NAME    DEPT
1   1       Bala    CSE     Poo     IT      Rajasekar   CSE     bhasker CSE

演示：

http://sqlfiddle.com/#!4/beb53/19

Answer 3

以下查询可能会对您有所帮助。

select
   id,
         rol_num,
   substr(SYS_CONNECT_BY_PATH(name, ','),2) name_list
from
   (
   select
     id,
         rol_num,
     name,
     count(*) OVER ( partition by id) cnt,
     ROW_NUMBER () OVER ( partition by id order by name) seq
   from test where id is not null)
where
   seq=cnt
start with
   seq=1
connect by prior
   seq+1=seq
and prior id=id;

输出

ID    ROL_NUM      NAME_LIST
1        1         Bala,Rajasekar

同样，您可以添加 dept_list。