【发布时间】:2017-11-14 16:51:30
【问题描述】:
我有一些数据想要重叠,如下所示。可能还有一些更聪明的方法,因为数据很大,请指教。
这是我的 VArray:
CREATE OR REPLACE TYPE NUMBER_VARRAY_5 AS VARRAY (5) OF NUMBER NOT NULL
这是原始数据(表 TEST_1)
"DATE_A","TOTO3_A"
"01/01/2005","281.25"
"02/01/2005","-9999.00"
"03/01/2005","291.50"
"04/01/2005","310.50"
"05/01/2005","298.75"
"06/01/2005","300.75"
表 TEST_2 是按日期滞后 1 天和固定天数(5 天)重叠的结果
"DATE_START","DATE_END","O3"
"01/01/2005","05/01/2005","<Collection>"
1 281.25
2 -9999
3 291.5
4 310.5
5 298.75
"02/01/2005","06/01/2005","<Collection>"
1 -9999
2 291.5
3 310.5
4 298.75
5 300.75
这是我的代码
CREATE OR REPLACE PROCEDURE TEST
IS
NUMBER_VARRAY NUMBER_VARRAY_5 := NUMBER_VARRAY_5 ();
L_VALUE NUMBER;
MIN_DATE DATE;
MAX_DATE DATE;
BEGIN
SELECT MIN (DATE_A), MAX (DATE_A)
INTO MIN_DATE, MAX_DATE
FROM TEST_1;
FOR CUR_R IN 0 .. (MAX_DATE - MIN_DATE - 4)
LOOP
L_VALUE := 0;
FOR I IN CUR_R .. (CUR_R + 4)
LOOP
L_VALUE := L_VALUE + 1;
NUMBER_VARRAY.EXTEND;
SELECT TOTO3_A
INTO NUMBER_VARRAY (L_VALUE)
FROM TEST_1
WHERE DATE_A = MIN_DATE + I;
END LOOP;
INSERT INTO TEST_2 (DATE_START, DATE_END, O3)
VALUES (MIN_DATE + CUR_R, (MIN_DATE + CUR_R + 4), NUMBER_VARRAY);
COMMIT;
NUMBER_VARRAY.DELETE ();
END LOOP;
END TEST;
【问题讨论】:
标签: sql oracle performance user-defined-types