使用 GROUP BY 和 ORDER BY pl/sql 获取结果集的 N 到 M 行 [重复]

Question

我需要转换以下查询以返回从任何 LOWERBOUND 到 UPPERBOUND（任何 N 到 M）的特定行数。

SELECT * FROM (
  SELECT 
    OWNER||','||HOSTNAME OWNER,
    SubStr(FILENAME,InStr(FILENAME,'/',-1)+1,Length(FILENAME)-InStr(FILENAME,'/',-1)+1)  a, 
    To_Date(SubStr(FILENAME,InStr(filename,'_',1)+1,14),'YYYYMMDDHH24MISS') STARTIME,
    servergrp Server_Group,
    filename, 
    Count(1) b  
  FROM patcheventlog  
  GROUP BY 
    OWNER||','||HOSTNAME ,
    SubStr(FILENAME,InStr(FILENAME,'/',-1)+1,Length(FILENAME)-InStr(FILENAME,'/',-1)+1)  ,  
    To_Date(SubStr(FILENAME,InStr(filename,'_',1)+1,14),'YYYYMMDDHH24MISS') ,
    servergrp,
    filename  
  order by 
    Startime desc 
)
where  
  rownum<=10

通过使用上面的 rownum 概念，我只能获得从第一行到定义的 rownum 的结果集。如上从 1 到 10。

所以请帮我解决这个问题。

谢谢

Answer 1

示例供参考。我们需要做到以下几点：

select * from (
select OWNER,a,STARTIME,Server_Group,filename,b ,row_number() over (order by STARTIME desc ) rnm from
(
  SELECT 
    OWNER||','||HOSTNAME OWNER,
    SubStr(FILENAME,InStr(FILENAME,'/',-1)+1,Length(FILENAME)-InStr(FILENAME,'/',-1)+1)  a, 
To_Date(SubStr(FILENAME,InStr(filename,'_',1)+1,14),'YYYYMMDDHH24MISS') STARTIME,
    servergrp Server_Group,
    filename, 
    Count(1) b  
  FROM patcheventlog  
  GROUP BY 
    OWNER||','||HOSTNAME ,
    SubStr(FILENAME,InStr(FILENAME,'/',-1)+1,Length(FILENAME)-InStr(FILENAME,'/',-1)+1)  ,  
    To_Date(SubStr(FILENAME,InStr(filename,'_',1)+1,14),'YYYYMMDDHH24MISS') ,
    servergrp,
    filename 
   ORDER BY 
    Startime desc )
) WHERE rnm BETWEEN 2 AND 7