列 SQL 百分比的总和答案

【问题标题】：Sum total of a column SQL Percentage列 SQL 百分比的总和
【发布时间】：2020-06-11 13:44:15
【问题描述】：

我正在尝试将最终记录作为计数和百分比的总和：

    SELECT  region,  count(*) as total, concat(to_char(round(count(*) * 100/ sum(count(*)) over() ,2),'990.99'),
'%') perc
FROM (SELECT 
    CASE
                 WHEN Substr(veh_vin, 1, 1) >= 'A' 
                      AND Substr(veh_vin, 1, 1) <= 'C' THEN 'America' 
                 WHEN Substr(veh_vin, 1, 1) >= 'J' 
                      AND Substr(veh_vin, 1, 1) <= 'R' THEN 'Poland' 
                 WHEN Substr(veh_vin, 1, 1) >= 'S' 
                      AND Substr(veh_vin, 1, 1) <= 'Z' THEN 'Euro' 
                 WHEN Substr(veh_vin, 1, 1) BETWEEN 1 AND 5 THEN 'North Africa' 
                 WHEN Substr(veh_vin, 1, 1) BETWEEN 6 AND 7 THEN 'Australia' 
                 WHEN Substr(veh_vin, 1, 1) BETWEEN 8 AND 9 THEN 'China' 
                 ELSE 'UNKNOWN' 
               END AS region 
        FROM   vehicle) s 
GROUP  BY region 
UNION 
SELECT 'Total' Region, 
       Count(*) TOTAL, 
       concat(to_char(count(*) * 100/ sum(count(*)) over(),'990.99'),
'%') perc       
FROM vehicle ;

我明白了：

        Region        TOTAL   PERC
         America       66     31.28%
         Poland        89     42.18%
         Europe         1     .47%
       Australia       1      .47%
         China        54      25.59%
          Total          211    100.00%

预计是：

    Region        TOTAL   PERC
     America       66     31.28%
     Poland        89     42.18%
     Europe         1     0.47%
   Australia       1      0.47%
     China        54      25.59%
   Total          211    99.99%

我正在尝试将 99.99 的值作为 perc 列的总和，我该怎么做？

【问题讨论】：

为什么要 99.99 而不是 100.00%？
尝试实际计算总百分比是没有意义的。你知道它已经是 100% 了，那为什么不直接使用文字值呢？
count(*) * 100/ sum(count(*)) over() 返回一个int，所以你做的回合没有效果，试试round(count(*) * 100.0/ sum(count(*)) over() ,2)（通知100.0），是你的问题吗？
这就是我要找的要求！ @戈登林诺夫
@nfgl 不，我编辑了我的问题，我得到 100.00，我需要 99.99，这是 Perc 列的总和。

标签： sql oracle join percentage

【解决方案1】：

这符合要求

with regions as (
SELECT  region,  count(*) as total, round(count(*) * 100/ sum(count(*)) over(),2) perc
FROM (SELECT 
    CASE
                 WHEN Substr(veh_vin, 1, 1) >= 'A' 
                      AND Substr(veh_vin, 1, 1) <= 'C' THEN 'America' 
                 WHEN Substr(veh_vin, 1, 1) >= 'J' 
                      AND Substr(veh_vin, 1, 1) <= 'R' THEN 'Poland' 
                 WHEN Substr(veh_vin, 1, 1) >= 'S' 
                      AND Substr(veh_vin, 1, 1) <= 'Z' THEN 'Euro' 
                 WHEN Substr(veh_vin, 1, 1) BETWEEN 1 AND 5 THEN 'North Africa' 
                 WHEN Substr(veh_vin, 1, 1) BETWEEN 6 AND 7 THEN 'Australia' 
                 WHEN Substr(veh_vin, 1, 1) BETWEEN 8 AND 9 THEN 'China' 
                 ELSE 'UNKNOWN' 
               END AS region 
        FROM   vehicle) s 
GROUP  BY region )
select region, total, concat(to_char(perc,'990.99'), '%') perc from regions
union all
select 'Total' region, sum(Total) total, concat(to_char(sum(Perc),'990.99'), '%') perc
from regions

【讨论】：