【问题标题】:Why am i getting ERROR 1064 (42000) mysql error on procedure?为什么我在程序上收到 ERROR 1064 (42000) mysql 错误?
【发布时间】:2016-05-18 15:42:33
【问题描述】:

我的 mysql 5.5 程序有什么问题? 我正在尝试通过 linux 上的 mysql 客户端命令终端创建它。

    DELIMITER //
CREATE procedure merge()
BEGIN

  DECLARE old_outlet_id INT(10);
  DECLARE new_outlet_id INT(10);
  DECLARE gpid VARCHAR(255);
  DECLARE v_finished INTEGER DEFAULT 0;
  DEClARE cur CURSOR FOR select distinct google_place_id from service_providers_outlets group by google_place_id having count(google_place_id) > 1;
  DECLARE CONTINUE HANDLER FOR NOT FOUND SET v_finished = 1;

  OPEN cur;


getC: LOOP

 FETCH cur INTO gpid;

 IF v_finished = 1 THEN 
 LEAVE getC;
 END IF;

     SET old_outlet_id = (select id from service_providers_outlets o where google_place_id = gpid order by created_on limit 1);
     SET new_outlet_id = (select id from service_providers_outlets o where google_place_id = gpid order by created_on desc limit 1); 

     select concat('old_outlet_id', old_outlet_id);
     select concat('new_outlet_id', new_outlet_id);

     if old_outlet_id != new_outlet_id then
         update reviews_completed set outlet_id = new_outlet_id where outlet_id = old_outlet_id;
         update service_providers_offers_outlet_link set outlet_id = new_outlet_id where outlet_id = old_outlet_id;
         update service_providers_offers_redeemed set outlet_id = new_outlet_id where outlet_id = old_outlet_id;
         update reviews_questions_outlet_link set outlet_id = new_outlet_id where outlet_id = old_outlet_id;
         delete from dashboard_users_outlet_link where outlet_id = old_outlet_id;
         delete from service_providers_outlets where id = old_outlet_id;
     end if;

 END LOOP getC;

 CLOSE cur;

END //
DELIMITER ;

我收到以下错误:

ERROR 1064 (42000):您的 SQL 语法有错误;检查 与您的 MySQL 服务器版本相对应的手册 在 'o where google_place_id = '' order by created_on 附近使用的语法 限制 1); ew_outlet_id = (select' at line 22 mysql> DELIMITER ;

【问题讨论】:

    标签: mysql sql stored-procedures


    【解决方案1】:

    尝试使用 max 和 min

    SET old_outlet_id = (select max(id) from service_providers_outlets o where google_place_id = '' );
    SET new_outlet_id = (select min(id) from service_providers_outlets o where google_place_id = ''); 
    

    【讨论】:

      猜你喜欢
      • 1970-01-01
      • 2023-01-08
      • 1970-01-01
      • 2011-12-06
      • 1970-01-01
      • 2019-02-21
      • 2014-07-05
      • 1970-01-01
      • 2018-03-05
      相关资源
      最近更新 更多