【发布时间】:2018-06-20 03:10:29
【问题描述】:
我已经建立了一个名为“捐赠”的表格。结构是这样的。
Id(P Key) 日期时间不能为 NULL CURRENT_TIMESTAMP
CName text utf32_bin 可以为NULL
EName text utf32_bin 可以为NULL
电话 int(20) 可以为 NULL
电子邮件文本 utf32_bin 可以为 NULL
地址文本utf32_bin可以为NULL
Ticket tinyint(1) 可以为 NULL
金额 int(255) 可以为 NULL
我尝试创建一个“创建”页面。
<?php
// Include config file
require_once 'database.php';
print_r($_POST);
// Define variables and initialize with empty values
$CName = $Address = $Amount = "";
$CName_err = $Address_err = $Amount_err = "";
// Processing form data when form is submitted
if($_SERVER["REQUEST_METHOD"] == "POST"){
// Validate name
$input_CName = trim($_POST["CName"]);
if(empty($input_CName)){
$CName_err = "Please enter a name.";
} elseif(!filter_var(trim($_POST["CName"]), FILTER_VALIDATE_REGEXP, array("options"=>array("regexp"=>"/^[a-zA-Z'-.\s ]+$/")))){
$CName_err = 'Please enter a valid name.';
} else{
$CName = $input_CName;
}
// Validate address
$input_Address = trim($_POST["Address"]);
if(empty($input_Address)){
$Address_err = 'Please enter an address.';
} else{
$Address = $input_Address;
}
// Validate Amount
$input_Amount = trim($_POST["Amount"]);
if(empty($input_Amount)){
$Amount_err = "Please enter the amount.";
} elseif(!ctype_digit($input_Amount)){
$Amount_err = 'Please enter a positive integer value.';
} else{
$Amount = $input_Amount;
}
// Check input errors before inserting in database
if(empty($CName_err) && empty($Address_err) && empty($Amount_err)){
// Prepare an insert statement
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "INSERT INTO donation (CName, Address, Amount) VALUES (?, ?, ?)";
$q = $pdo->prepare($sql);
$q->execute(array($name,$email,$mobile));
Database::disconnect();
header("Location: index.php");
}}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Create Record</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.css">
<style type="text/css">
.wrapper{
width: 500px;
margin: 0 auto;
}
</style>
</head>
<body>
<div class="wrapper">
<div class="container-fluid">
<div class="row">
<div class="col-md-12">
<div class="page-header">
<h2>Create Record</h2>
</div>
<p>Please fill this form and submit to add employee record to the database.</p>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<div class="form-group <?php echo (!empty($CName_err)) ? 'has-error' : ''; ?>">
<label>Name</label>
<input type="text" name="CName" class="form-control" value="<?php echo $CName; ?>">
<span class="help-block"><?php echo $CName_err;?></span>
</div>
<div class="form-group <?php echo (!empty($Address_err)) ? 'has-error' : ''; ?>">
<label>Address</label>
<textarea name="Address" class="form-control"><?php echo $Address; ?></textarea>
<span class="help-block"><?php echo $Address_err;?></span>
</div>
<div class="form-group <?php echo (!empty($Amount_err)) ? 'has-error' : ''; ?>">
<label>Amount</label>
<input type="text" name="Amount" class="form-control" value="<?php echo $Amount; ?>">
<span class="help-block"><?php echo $Amount_err;?></span>
</div>
<input type="submit" class="btn btn-primary" value="Submit">
<a href="index.php" class="btn btn-default">Cancel</a>
</form>
</div>
</div>
</div>
</div>
</body>
</html>
我尝试将CName、Address、Amount 提交到数据库中。
没有任何东西被传递到 CName , Address , Amount 。
但是新的一行记录是真的创建的,ID是根据CURRENT_TIMESTAMP创建的。
我真的怀疑发生了一些数据库连接问题。
数据库.php
<?php
class Database
{
private static $dbName = 'donaton_info' ;
private static $dbHost = 'localhost' ;
private static $dbUsername = 'root';
private static $dbUserPassword = '1234';
private static $cont = null;
public function __construct() {
die('Init function is not allowed');
}
public static function connect()
{
// One connection through whole application
if ( null == self::$cont )
{
try
{
self::$cont = new PDO( "mysql:host=".self::$dbHost.";"."dbname=".self::$dbName, self::$dbUsername, self::$dbUserPassword );
}
catch(PDOException $e)
{
die($e->getMessage());
}
}
return self::$cont;
}
public static function disconnect()
{
self::$cont = null;
}
}
?>
【问题讨论】:
-
数据库连接问题会导致您无法连接到数据库。这里的问题出在您的插入查询中。
标签: php html mysql sql database