【发布时间】:2016-12-27 14:54:15
【问题描述】:
我正在编写一个简单的 CASE 代码,以便在员工赚取更多部门的 AVG 工资时打印在屏幕上。但是我不明白为什么当我想检查 2 名员工的工资时,我在屏幕上只看到一个结果。我希望你能理解我的问题。谢谢。
SET SERVEROUTPUT ON
DECLARE
v_emp121_sal employees.salary%TYPE;
v_emp121_lname employees.last_name%TYPE;
v_emp139_sal employees.salary%TYPE;
v_emp139_lname employees.last_name%TYPE;
v_avgsal employees.salary%TYPE;
BEGIN
SELECT salary, last_name
INTO v_emp121_sal, v_emp121_lname
FROM employees
WHERE employee_id = 121;
DBMS_OUTPUT.PUT_LINE('EMPLOYEE 121 SALARY IS: ' || v_emp121_sal);
SELECT salary, last_name
INTO v_emp139_sal, v_emp139_lname
FROM employees
WHERE employee_id = 139;
DBMS_OUTPUT.PUT_LINE('EMPLOYEE 139 SALARY IS: ' || v_emp139_sal);
SELECT AVG(salary)
INTO v_avgsal
FROM employees
WHERE department_id = 50;
DBMS_OUTPUT.PUT_LINE('DEPARTMENT 50 AVG SALARY IS: ' ||
TRUNC(v_avgsal, 0));
CASE
WHEN
v_emp121_sal < v_avgsal THEN
DBMS_OUTPUT.PUT_LINE('SALARY OF EMP ' || v_emp121_lname ||
' IS LESS THAN DEPARTMENT AVG');
WHEN
v_emp121_sal > v_avgsal THEN
DBMS_OUTPUT.PUT_LINE('SALARY OF EMP ' || v_emp121_lname ||
' IS HIGHER THAN AVG DEPARTMENT');
WHEN
v_emp139_sal < v_avgsal THEN
DBMS_OUTPUT.PUT_LINE('SALARY OF EMP ' || v_emp139_lname ||
' IS LESS THAN DEPARTMENT AVG');
WHEN
v_emp139_sal > v_avgsal THEN
DBMS_OUTPUT.PUT_LINE('SALARY OF EMP ' || v_emp139_lname ||
' IS HIGHER THAN AVG DEPARTMENT');
END CASE;
END;
/
理论上,我应该在屏幕上收到 “EMP FRIPP 的薪水高于平均部门” "EMP SEO 的薪水低于平均部门"
【问题讨论】:
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工资号码(8, 2)
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rattlesnake..你可以在这里发布你的工作代码供其他人参考