每个结果多行的 SQL Pivot

Question

我正在尝试了解如何使用 Advantage Database Server 调整日期。

我有以下代码，它将（使用 CASE）我们的月度销售数据：

    SELECT YEAR(date) as MyYear
     , SUM(CASE WHEN MONTH(date) =  1 THEN value END) jan_revenue
     , SUM(CASE WHEN MONTH(date) =  1 THEN value - (qty*ekp/pe) END) jan_margin
     , SUM(CASE WHEN MONTH(date) =  2 THEN value END) feb_revenue
     , SUM(CASE WHEN MONTH(date) =  2 THEN value - (qty*ekp/pe) END) feb_margin
     , SUM(CASE WHEN MONTH(date) =  3 THEN value END) mar_revenue
     , SUM(CASE WHEN MONTH(date) =  3 THEN value - (qty*ekp/pe) END) mar_margin
  FROM (SELECT DAB020.*
             , EXTRACT(YEAR  FROM date) year
             , EXTRACT(MONTH FROM date) month
       FROM "DAB020.ADT" DAB020
          where buart = 'A' and auf_kumsta = 'J' and date >= '2021-01-01'
       ) mysalesdata
 GROUP BY YEAR(date)

这会产生如下所示的结果：

MyYear  jan_revenue jan_margin  feb_revenue jan_margin_1    mar_revenue jan_margin_2
2021    23123414    12312323    4554535     545345          435345      123123

我真正想要的是让收入和利润处于不同的线上：

MyYear  TYPE    jan         Feb         Mar 
2021    Revenue 23123414    12312323    4554535    
2021    Margin  545345      435345      123123

（数字是假的，但你明白了）

我该怎么做？我确信 CASE 和 Grouping 的组合是解决方案，但我无法解决。

（编辑：据我所知，ADS 中没有枢轴功能）

Answer 1

反透视数据以获得不同行的利润和收入。然后像现在这样聚合：

SELECT YEAR(date) as MyYear, type, 
       SUM(CASE WHEN MONTH(date) =  1 THEN value END) as jan,
       SUM(CASE WHEN MONTH(date) =  2 THEN value END) as feb,
       SUM(CASE WHEN MONTH(date) =  3 THEN value END) as mar
FROM (SELECT DAB020.*
      FROM (SELECT date, 'revenue' as type, value, buart, aufkumsta
            FROM "DAB020.ADT" UNION ALL
            SELECT date, 'margin' as type, value - (qty*ekp/pe), buart, aufkumsta
            FROM "DAB020.ADT"
           ) DAB020
      WHERE buart = 'A' AND auf_kumsta = 'J' AND
            date >= '2021-01-01'
     ) mysalesdata
 GROUP BY YEAR(date)