sql 2005 对动态数据进行分组

Question

我有这样的数据

Investor    Contact
IBM           James  
IBM           Dean  
IBM           Sean  
Microsoft     Bill  
Microsoft     Steve

我需要数据看起来像这样

Investor     Contact
IBM          James,Dean,Sean  
Microsoft    Bill,Steve  

或者如果以上是不可能的

Investor        Contact1  Contact2   Contact3  ...
IBM             James      Dean        Sean  
Microsoft        Bill      Steve

Answer 1

这应该可行：

SELECT Investor, 
STUFF((
    SELECT ',' + convert(nvarchar(50), Contact) 
    FROM Investors I2
    WHERE I2.Investor = I1.Investor
    FOR XML PATH('')
), 1, 1, '') Contacts
FROM Investors I1
GROUP BY Investor

结果：

IBM       James,Dean,Sean
Microsoft   Bill,Steve

Answer 2

试试下面的方法来让你的逗号分隔列表继续下去。我将不得不更多地使用它来弄清楚如何让分组工作。

DECLARE @listStr VARCHAR(MAX)
SELECT @listStr = COALESCE(@listStr+',' , '') + Contact
FROM InvestorContact
SELECT @listStr

Answer 3

以防万一您的任何联系人的姓名中包含特殊的 XML 字符：the Tony Rogerson approach。

;with data as
(
SELECT 'IBM' Investor,  'James' Contact UNION ALL  
SELECT 'IBM' ,          'Dean'  Contact UNION ALL  
SELECT 'IBM' ,          'Sean'  Contact UNION ALL  
SELECT 'Microsoft' ,    'Bill'  Contact UNION ALL    
SELECT 'Microsoft',     'Steve' Contact
)
SELECT Investor, 
   stuff((SELECT mydata
   FROM (
      SELECT ',' + Contact  AS [data()]
      FROM
      data AS d2
      WHERE d2.Investor = d1.Investor
      FOR XML PATH(''), TYPE
   ) AS d ( mydata ) FOR XML RAW, TYPE ).value( '/row[1]/mydata[1]', 'varchar(max)' )
, 1, 1, '')
FROM data d1
GROUP BY Investor