【问题标题】:Select Top 1 with Switch Statement and Left join Access SQL使用 Switch 语句和左连接 Access SQL 选择 Top 1
【发布时间】:2016-08-24 15:42:01
【问题描述】:

所以我不确定我把这个 Access SQL 查询搞砸了多少,但它相当复杂。

场景如下:有三个表。一种称为“PriceMatrix”,一种称为“PreApprovedPricing”,最后一种称为“Request”。已批准的定价包含按州列出的“已批准”价格列表,“价格矩阵”包含从另一个来源生成的价格列表,请求是所有这些都指向的父记录(也包含州)。我正在尝试编写一个查询来比较每个表中的价格,如果预先批准的价格小于价格矩阵中的价格,它会替换字段中的值,但如果大于,则保留原价矩阵价格。我尝试使用 switch 语句来查看给定的状态。

这是我的查询:

SELECT TOP 1 [ApprovedPrice] from [PreApprovedPricing] AS [1stMonthApproved] WHERE [ApprovedPrice] >= [PriceMatrix].[1stMonth]
ORDER BY [ApprovedPrice] ASC,
SWITCH( Request.[state] = 'CT' , [1stMonthApproved], Request.[state] = 'MA' , [1stMonthApproved], 1=1 ,  [PriceMatrix].[1stMonth]) AS 1stMonth,
FROM PriceMatrix LEFT JOIN Request ON PriceMatrix.RequestID = Request.RequestID;

我不断收到语法错误,但我似乎无法深入了解问题的根源。所以任何输入都会很棒,因为我还在学习 SQL

【问题讨论】:

    标签: sql ms-access


    【解决方案1】:

    您不能有多个 From 子句。你的陈述

    SELECT TOP 1 [ApprovedPrice] 
    from [PreApprovedPricing] AS [1stMonthApproved] 
    WHERE [ApprovedPrice] >= [PriceMatrix].[1stMonth]
    ORDER BY [ApprovedPrice] ASC,
    SWITCH( Request.[state] = 'CT' , [1stMonthApproved], Request.[state] = 'MA' , [1stMonthApproved], 1=1 ,  [PriceMatrix].[1stMonth]) AS 1stMonth,
    FROM PriceMatrix 
    LEFT JOIN Request ON PriceMatrix.RequestID = Request.RequestID;
    

    其实是:

    Select Top
    From
    Where
    Order by
    From
    Left Join
    

    那肯定会出现语法错误。我假设您想要在某个地方进行子查询。也许像这样(但很难确定):

    SELECT [ApprovedPrice] ,
        (Select top 1 SWITCH( Request.[state] = 'CT' , [1stMonthApproved], Request.[state] = 'MA' , [1stMonthApproved], 1=1 ,  [PriceMatrix].[1stMonth])
        from [PreApprovedPricing] AS [1stMonthApproved] 
        WHERE [ApprovedPrice] >= [PriceMatrix].[1stMonth]
        ORDER BY [ApprovedPrice] ASC,
            SWITCH( Request.[state] = 'CT' , [1stMonthApproved], Request.[state] = 'MA' , [1stMonthApproved], 1=1 ,  [PriceMatrix].[1stMonth])) AS 1stMonth
    FROM PriceMatrix 
    LEFT JOIN Request ON PriceMatrix.RequestID = Request.RequestID;
    

    【讨论】:

    • 酷谢谢布拉德,我已经得到了语法错误,停止将前 1 条语句视为子查询,但现在我得到奇怪的值,我认为我只需要评估逻辑查询本身。所以如果我需要我的逻辑方面的帮助,我会提出另一个帮助问题,但你的回答解决了语法的根本问题,谢谢!
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