【问题标题】:Informix, Initializing variables in a stored procedureInformix,在存储过程中初始化变量
【发布时间】:2010-06-03 19:02:50
【问题描述】:

我在 Informix 数据库上有一个存储过程。我想从该过程的执行中获取一些变量。

我不知道如何创建存储过程。

这是我目前所拥有的:

CREATE PROCEDURE foo()
RETURN somebar;
END PROCEDURE;

当我运行它时,我得到一个错误:

DEFINE somebar

我想这样做:

execute procedure foo() into bar;

如何执行过程 foo() 并将返回值放入 bar?

【问题讨论】:

    标签: informix spl


    【解决方案1】:

    这是一个插图。基本上,RETURNING 子句列出了类型(可选地后跟 AS 名称 - 但名称不声明变量);然后在过程的主体中“像往常一样”定义变量,然后返回它们。

    这个特定示例是 Oracle 的 NEXT_DAY 函数的模拟,减去了全球化。该文件包含自检:

    示例过程

    -- @(#)$Id: next_day.spl,v 1.1 2004/10/05 21:39:18 jleffler Exp $
    --
    -- @(#)Create procedure equivalent to Oracle's NEXT_DAY() function.
    -- Bugs: not internationalized.
    
    CREATE PROCEDURE 'oracle'.next_day(dateval DATE, dayname CHAR(3))
        RETURNING DATE AS next_date;
    
        DEFINE rv DATE;     -- Return value.
        DEFINE dw INTEGER;  -- Weekday corresponding to dayname.
        DEFINE wd INTEGER;  -- Weekday corresponding to dateval.
        DEFINE dn CHAR(3);
    
        LET rv = NULL;
    
        IF dateval IS NOT NULL THEN
            LET dw = NULL;
            LET dn = UPPER(dayname);
            IF   dn = 'SUN' THEN LET dw = 0;
            ELIF dn = 'MON' THEN LET dw = 1;
            ELIF dn = 'TUE' THEN LET dw = 2;
            ELIF dn = 'WED' THEN LET dw = 3;
            ELIF dn = 'THU' THEN LET dw = 4;
            ELIF dn = 'FRI' THEN LET dw = 5;
            ELIF dn = 'SAT' THEN LET dw = 6;
            END IF;
            IF dw IS NOT NULL THEN
                LET wd = WEEKDAY(dateval);
                LET rv = dateval - wd + dw;
                IF wd >= dw THEN
                    LET rv = rv + 7;
                END IF;
            END IF;
        END IF;
    
        RETURN rv;
    
    END PROCEDURE;
    

    自检代码

    --     February 2001
    --   S  M Tu  W Th  F  S
    --               1  2  3
    --   4  5  6  7  8  9 10
    --  11 12 13 14 15 16 17
    --  18 19 20 21 22 23 24
    --  25 26 27 28
    
    CREATE TEMP TABLE test_next_day
    (
        ref_date    DATE NOT NULL,
        nxt_day     CHAR(9) NOT NULL,
        exp_date    DATE NOT NULL
    );
    
    INSERT INTO test_next_day VALUES(MDY(02,01,2001), 'Tuesday',   MDY(02,06,2001));
    INSERT INTO test_next_day VALUES(MDY(02,02,2001), 'Tuesday',   MDY(02,06,2001));
    INSERT INTO test_next_day VALUES(MDY(02,03,2001), 'Tuesday',   MDY(02,06,2001));
    INSERT INTO test_next_day VALUES(MDY(02,04,2001), 'Tuesday',   MDY(02,06,2001));
    INSERT INTO test_next_day VALUES(MDY(02,05,2001), 'Tuesday',   MDY(02,06,2001));
    INSERT INTO test_next_day VALUES(MDY(02,06,2001), 'Tuesday',   MDY(02,13,2001));
    INSERT INTO test_next_day VALUES(MDY(02,07,2001), 'Tuesday',   MDY(02,13,2001));
    INSERT INTO test_next_day VALUES(MDY(02,02,2001), 'Monday',    MDY(02,05,2001));
    INSERT INTO test_next_day VALUES(MDY(02,02,2001), 'Wednesday', MDY(02,07,2001));
    INSERT INTO test_next_day VALUES(MDY(02,02,2001), 'Thursday',  MDY(02,08,2001));
    INSERT INTO test_next_day VALUES(MDY(02,02,2001), 'Friday',    MDY(02,09,2001));
    INSERT INTO test_next_day VALUES(MDY(02,02,2001), 'Saturday',  MDY(02,03,2001));
    INSERT INTO test_next_day VALUES(MDY(02,02,2001), 'Sunday',    MDY(02,04,2001));
    
    SELECT ref_date, nxt_day, WEEKDAY(ref_date) AS ref_dow,
           exp_date, WEEKDAY(exp_date) AS exp_dow,
           NEXT_DAY(ref_date, nxt_day) AS got_date
        FROM test_next_day
        INTO TEMP test_next_day2;
    
    SELECT *
        FROM test_next_day2
        ORDER BY ref_date, nxt_day;
    
    SELECT "**FAILED**" AS failed, *
        FROM test_next_day2
        WHERE (exp_date IS NOT NULL AND got_date IS     NULL)
           OR (exp_date IS     NULL AND got_date IS NOT NULL)
           OR (exp_date IS NOT NULL AND got_date IS NOT NULL AND exp_date != got_date)
        ORDER BY ref_date, nxt_day;
    

    【讨论】:

    • 你太棒了!我不知道该怎么说。它真的帮助了我。谢谢兄弟!
    • @santiagobasulto:围绕 StackOverflow 网站三部曲,说“谢谢”的习惯方式是投票和/或“接受的答案”。
    • 你是对的。对此感到抱歉。再次感谢。您是 Informix DBA 吗?
    • @santiago:只是兼职,但就像我的个人资料所说的那样,我使用 Informix 已经很长时间了 - 还不到 25 年,但也不远了。
    猜你喜欢
    • 1970-01-01
    • 2010-09-16
    • 1970-01-01
    • 2012-07-28
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    相关资源
    最近更新 更多