【发布时间】:2020-06-09 17:10:40
【问题描述】:
我试图从 Java Web App 的输入中简单地将 base64 加密密码存储在数据库中。
我为此使用 hsqldb,我的密码列类型是 varbinary(255)。 但是当我尝试将它存储在数据库中时,我只会收到以下错误。我什至尝试将密码列的类型更改为 BLOB 或 varchar,但它仍然给我同样的错误。请帮忙。
错误:
com.loginjava.exception.LoginException: Not possible to update the password
at com.loginjava.classes.PasswordHandler.UpdatePassword(PasswordHandler.java:36)
at com.loginjava.servlets.ForgotPasswordReset.doPost(ForgotPasswordReset.java:55)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:660)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:741)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:231)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:53)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:202)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:96)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:541)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:139)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:92)
at org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:690)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:74)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:343)
at org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:373)
at org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:65)
at org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:868)
at org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1590)
at org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
at java.base/java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1128)
at java.base/java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:628)
at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
at java.base/java.lang.Thread.run(Thread.java:830)
Caused by: java.sql.SQLDataException: data exception: invalid character value for cast
at org.hsqldb.jdbc.JDBCUtil.sqlException(Unknown Source)
at org.hsqldb.jdbc.JDBCUtil.sqlException(Unknown Source)
at org.hsqldb.jdbc.JDBCPreparedStatement.setParameter(Unknown Source)
at org.hsqldb.jdbc.JDBCPreparedStatement.setString(Unknown Source)
at org.apache.tomcat.dbcp.dbcp2.DelegatingPreparedStatement.setString(DelegatingPreparedStatement.java:616)
at org.apache.tomcat.dbcp.dbcp2.DelegatingPreparedStatement.setString(DelegatingPreparedStatement.java:616)
at com.loginjava.classes.PasswordHandler.UpdatePassword(PasswordHandler.java:26)
... 25 more
Caused by: org.hsqldb.HsqlException: data exception: invalid character value for cast
at org.hsqldb.error.Error.error(Unknown Source)
at org.hsqldb.error.Error.error(Unknown Source)
at org.hsqldb.Scanner.convertToBinary(Unknown Source)
at org.hsqldb.types.BinaryType.castOrConvertToType(Unknown Source)
at org.hsqldb.types.BinaryType.convertToDefaultType(Unknown Source)
... 30 more
这是我的 Servlet:
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String password = request.getParameter("password");
String token = request.getParameter("token");
if(PasswordHandler.CheckRequirements(password)) {
String encryptedpwd = Base64.getEncoder().encodeToString(password.getBytes());
try {
PasswordHandler.UpdatePassword(encryptedpwd, token);
} catch (SQLException e) {
e.printStackTrace();
}
String message = Constants.PWD_SUCCESS;
request.setAttribute("message", message);
request.getRequestDispatcher("reset-password.jsp?token=" + token).forward(request, response);
} else {
String message = Constants.PWD_FAIL;
request.setAttribute("message", message);
request.getRequestDispatcher("reset-password.jsp?token=" + token).forward(request, response);
}
}
这是 PasswordHandler.java 类:
public static void UpdatePassword(String encryptedpwd, String token) throws SQLException {
try
{
PreparedStatement ps = con.prepareStatement(
"UPDATE user SET password = ? WHERE token = ?");
ps.setString(1,encryptedpwd);
ps.setString(2,token);
ps.executeUpdate();
ps.close();
}
catch (Exception e) {
throw new LoginException("Not possible to update the password", e);
}
}
【问题讨论】:
-
base64 不是加密的。不要将明文密码存储在数据库中。曾经。 (另外,不要将加密密码存储在数据库中,但这是一个不同的讨论)
-
为什么您的密码列不是字符串?似乎您的 base64-String 无法转换为 varbinary
标签: java encryption base64 hsqldb