【发布时间】:2016-10-15 15:57:17
【问题描述】:
我需要通过以下方式在我的排名页面上显示列表
Team_Name Played Won Lost Points In_Top_3
Some Team 5 5 0 11 Yes
积分计算方式为
2 分/比赛获胜
如果比赛获胜是四分之一决赛,则+1
如果比赛是半决赛获胜,则+2
+3 如果比赛获胜是大结局
我成功地实现了其中的大多数,但其中一个是 In_Top_3,尽管有一个便宜的解决方法来添加 $count 并检查它是否为 <=3 并在列下显示是,但我有什么办法可以做使用 SQL 查询。
我目前的SQL查询如下
SELECT
T.id, T.name, T.status, IFNULL(T.image, 'no-image.png') AS DP,
(SELECT COUNT(*)
FROM badminton_matches MT
WHERE (MT.team_one = T.id OR MT.team_two = T.id))
AS played,
(SELECT COUNT(*)
FROM badminton_match_results R
WHERE R.winner_id = T.id) AS won,
(SELECT COUNT(*)
FROM badminton_matches MT JOIN badminton_match_results MR
ON (MR.match_id = MT.id)
WHERE (MT.team_one = T.id OR MT.team_two = T.id) AND MR.winner_id != T.id) AS lost,
(
((SELECT COUNT(*)
FROM badminton_match_results R
WHERE R.winner_id = T.id) * 2)
+
((SELECT COUNT(*)
FROM badminton_match_results R JOIN badminton_matches M ON (M.id = R.match_id AND M.match_type = 'quarter')
WHERE R.winner_id = T.id))
) AS Points
FROM badminton_teams T
ORDER BY (Points) DESC
当我有以下表结构时,我如何标记排名前 3 的团队以及我当前的查询,并且
表格:团队
+------------+----------------------------+------+-----+-------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+----------------------------+------+-----+-------------------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(150) | NO | | NULL | |
| image | text | YES | | NULL | |
| status | enum('active','in-active') | NO | | active | |
| added_on | datetime | NO | | CURRENT_TIMESTAMP | |
| updated_on | datetime | YES | | NULL | |
+------------+----------------------------+------+-----+-------------------+----------------+
表格:匹配
+------------+---------------------------------------+------+-----+-------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+---------------------------------------+------+-----+-------------------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| team_one | int(11) | NO | MUL | NULL | |
| team_two | int(11) | NO | | NULL | |
| added_on | datetime | NO | | CURRENT_TIMESTAMP | |
| match_type | enum('pool','quarter','semi','final') | NO | | pool | |
| sets | smallint(2) | NO | | 1 | |
+------------+---------------------------------------+------+-----+-------------------+----------------+
表格:匹配结果
+-----------+----------+------+-----+-------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+----------+------+-----+-------------------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| match_id | int(11) | NO | MUL | NULL | |
| winner_id | int(11) | NO | MUL | NULL | |
| added_on | datetime | NO | | CURRENT_TIMESTAMP | |
+-----------+----------+------+-----+-------------------+----------------+
【问题讨论】:
-
在应用程序代码中使用计数器可能是最好的解决方案。但是如果时间不多,可以搜索“mysql+rank”。
-
我不确定,但你可以通过
CASE查看计数。
标签: mysql