【问题标题】:Pig: Count Frequency of distinct Tuples in a filePig:文件中不同元组的计数频率
【发布时间】:2016-10-08 01:02:09
【问题描述】:

我有一个包含 json 条目的文件,如下所示:

{"child_pos": "NN", "parent_pos": "NN", "parent": "fighter", "child_dep": "nn", "parent_dep": "nsubj", "child": "virtua"}
{"child_pos": "NN", "parent_pos": "NN", "parent": "case", "child_dep": "nn", "parent_dep": "nsubj", "child": "martin"}
{"child_pos": "NN", "parent_pos": "NN", "parent": "fighter", "child_dep": "nn", "parent_dep": "nsubj", "child": "virtua"}
{"child_pos": "NN", "parent_pos": "NN", "parent": "fighter", "child_dep": "nn", "parent_dep": "nsubj", "child": "virtua"}
{"child_pos": "NN", "parent_pos": "NN", "parent": "case", "child_dep": "nn", "parent_dep": "nsubj", "child": "martin"}

我想计算文件中不同 json 对象的频率。我看到了我们在 Pig 中使用 Group By 和 count() 函数的其他答案。我不确定我是否正确使用它们,但我没有得到所需的结果。我的输出应该是这样的:

{"child_pos": "NN", "parent_pos": "NN", "parent": "fighter", "child_dep": "nn", "parent_dep": "nsubj", "child": "virtua", "count": "3"}
{"child_pos": "NN", "parent_pos": "NN", "parent": "case", "child_dep": "nn", "parent_dep": "nsubj", "child": "martin", "count": "2"}

顺序并不重要。有人可以给我一些指点吗?

【问题讨论】:

  • 请分享您尝试过的方法以及为什么您认为这不起作用?

标签: json count apache-pig


【解决方案1】:

这里是可以使用的代码,所有字段的条件都被分组如果你想要其他格式,你可以从元组中读取字段并使用任何其他格式

A = LOAD '/user/root/test12.json' USING JsonLoader('child_pos:chararray,               parent_pos:chararray, parent:chararray, child_dep:chararray, parent_dep:chararray, child:chararray');
B = GROUp A by (child_pos, parent_pos, parent, child_dep, parent_dep, child) ;
C = FOREACH B GENERATE group, COUNT(A.child_pos) as COUNTX;
STORE C into 'user/data/json_out.json' USING JsonStorage();

out put is ... 
{"group":    {"child_pos":"NN","parent_pos":"NN","parent":"case","child_dep":"nn","parent_dep":"nsubj","child":"martin"},"COUNTX":2}
{"group":{"child_pos":"NN","parent_pos":"NN","parent":"fighter","child_dep":"nn","parent_dep":"nsubj","child":"virtua"},"COUNTX":3}

【讨论】:

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