【发布时间】:2017-08-15 09:23:43
【问题描述】:
我在 PySpark 中使用了一个具有分类特征的数据集,这些特征被索引和 one-hot 编码。拟合管道后,我使用特征列的元数据提取编码特征。当我在管道中包含规范器时,我会丢失分类特征的元数据。请参见下面的示例:
train.show()
+-----+---+----+----+
|admit|gre| gpa|rank|
+-----+---+----+----+
| 0.0|380|3.61| 3|
| 1.0|660|3.67| 3|
| 1.0|800| 4.0| 1|
| 1.0|640|3.19| 4|
| 0.0|520|2.93| 4|
+-----+---+----+----+
from pyspark.ml.feature import StringIndexer, OneHotEncoder, VectorAssembler, Normalizer
#indexer for categorical features
rank_indexer = StringIndexer(inputCol = 'rank', outputCol = 'rank_ind', handleInvalid="skip")
#encoder for categorical features
rank_encoder = OneHotEncoder(inputCol = 'rank_ind', outputCol = 'rank_enc')
# assembler
assembler = VectorAssembler(inputCols=['gre','gpa','rank_enc'], outputCol="featuresVect")
# Create the normalizer
normalizer = Normalizer(inputCol="featuresVect", outputCol="features", p=1.0)
stages = [rank_indexer] + [rank_encoder] + [assembler] + [normalizer]
from pyspark.ml import Pipeline
final_pipeline = Pipeline(
stages = stages
)
pipelineModel = final_pipeline.fit(train)
data = pipelineModel.transform(train)
data.schema['features'].metadata
{}
## empty dictionary
## excluding the normalizer results in this metadata:
{u'ml_attr': {u'attrs': {u'binary': [{u'idx': 2, u'name': u'rank_enc_2'},
{u'idx': 3, u'name': u'rank_enc_3'},
{u'idx': 4, u'name': u'rank_enc_4'}],
u'numeric': [{u'idx': 0, u'name': u'gre'}, {u'idx': 1, u'name': u'gpa'}]},
u'num_attrs': 5}}
这是正常行为吗?如何在不丢失此元数据的情况下包含规范化器?
【问题讨论】:
标签: apache-spark pyspark metadata apache-spark-ml normalize