【发布时间】:2020-08-10 09:20:32
【问题描述】:
我需要插入到 Hive 的表中。仅供参考,此表在 Hive 中可用。这是我的代码,
from pyspark.sql import SparkSession as sc, HiveContext as HC
spark = sc.builder.appName('eap').enableHiveSupport().getOrCreate()
sqlContext = HC(spark)
sqlContext.sql("INSERT INTO mydb.my_job_status_table
SELECT st.tablename, fs.finalhivetable, ss.lastrunid, fs.status, b.id, b.rungroup, ss.starttime, fs.endtime
FROM batches b
inner join sourcetables st on b.rungroup = st.rungroup
inner join stagingstatus ss on b.id = ss.batchid and st.id = ss.tableid
inner join finalstatus fs on b.id = fs.batchid and st.id = fs.tableid
WHERE b.rungroup like 'sgb_%'")
在 Spark 中运行代码后,我收到了一个错误,
raise ParseException(s.split(': ', 1)[1], stackTrace)
pyspark.sql.utils.ParseException: u"\nmismatched input '01' expecting <EOF>(line 1, pos 195)\n\n== SQL ==\nINSERT INTO mydb.my_job_status_table...
我做错了什么? SqlContext 和 Spark.sql 有什么区别?
【问题讨论】:
标签: apache-spark pyspark hive sql-insert