嗯,mllib.Vectors 已经提供了有意义的字符串表示和fromString 方法:
from pyspark.mllib.linalg import Vectors, SparseVector
v = SparseVector(5, [0, 3], [1.0, -1.0])
str(v)
## '(5,[0,3],[1.0,-1.0])'
assert Vectors.parse(str(v)) == v
import org.apache.spark.mllib.linalg.{Vectors, Vector}
Vectors.parse("(5,[0,3],[1.0,-1.0])")
// org.apache.spark.mllib.linalg.Vector = (5,[0,3],[1.0,-1.0])
如果您想避免使用纯文本,那么 Parquet 是另一种开箱即用的选项:
(sc.parallelize([(SparseVector(5, [0, 3], [1.0, -1.0]), )])
.toDF()
.write
.parquet("/tmp/foo"))
val df = sqlContext.read.parquet("/tmp/foo")
df.printSchema()
// root
// |-- _1: vector (nullable = true)