【发布时间】:2020-01-28 13:54:31
【问题描述】:
我有一个如下的数据框:
+-----------------------------------------------------------------+
|ID|DATASET |
+-----------------------------------------------------------------+
|4A|[{"col.1":"12ABC","col.2":"141","col.3":"","col.4":"ABCD"}] |
|8B|[{"col.1":"12ABC","col.2":"141","col.3":"","col.4":"ABCD"}] |
+-----------------------------------------------------------------+
预期输出:
+----------------------------------+
|ID|col_1 | col_2 | col_3| col_4 |
+----------------------------------+
|4A|"12ABC"|"141"||"ABCD" |
|8B|"12ABC"|"141"||"ABCD" |
+--------------------------------- +
- 我尝试使用 regex_extract:
df.withColumn("col_1", regexp_extract("DATASET", "(?
但在结果中得到空值
+----------------------------------+
|ID|col_1 | col_2 | col_3| col_4 |
+----------------------------------+
|4A|||| |
|8B|||| |
+--------------------------------- +
对此的任何意见
提前致谢
已编辑
感谢您的回复,效果很好,我的输入发生了一些变化,我想根据 col1 进行分组并将值放在单独的行中
更新数据集:
+---------------------------------------------------------------------------------------------------------------------------+
|ID|DATASET |
+---------------------------------------------------------------------------------------------------------------------------+
|4A|[{"col.1":"12ABC","col.2":"141","col.3":"","col.4":"ABCD"},{"col.1":"13ABC","col.2":"141","col.3":"","col.4":"ABCD"}] |
+---------------------------------------------------------------------------------------------------------------------------+
预期结果:
+-----------------------------------------------------------------+
|ID|col_1 | col_2 | col |
+-----------------------------------------------------------------+
|4A|"12ABC"|"{"col.2":"141","col.3":"","col.4":"ABCD"}" |
|4A|"13ABC"|"{"col.2":"141","col.3":"","col.4":"ABCD"}" |
+-----------------------------------------------------------------+
提前致谢
【问题讨论】:
标签: regex pyspark pyspark-dataframes