【问题标题】:How can I simplify the SQL below and improve performance?如何简化下面的 SQL 并提高性能?
【发布时间】:2020-09-17 02:57:54
【问题描述】:

我正在尝试使用内联视图仅提取一行八列。

但是,有相当多的重叠。我不擅长使用 PL/SQL。

如何简化 SQL 代码并提高查询性能?

我在“CARD_NUM”列和“CARD_TRANSACTION_TIME”列中创建了 INDEX。
性能提升不少,但有1000万数据,还是有延迟的。

感谢您的帮助。

WITH WHOLE AS (SELECT CARD_TRANSACTION_TIME, CARD_TRANSACTION_AMOUNT, CARD_TRANSACTION_CONTENT, INDUSTRY_CODE
                FROM CARD_TRANSACTION_TEST01
                WHERE CARD_NUM IN(SELECT CARD_NUM FROM CARD_CONTRACT_TEST01 WHERE RESI_NUM = '9203101937988')
                      AND TO_CHAR(CARD_TRANSACTION_TIME, 'YYYY') = '2020' 
                      AND TO_CHAR(CARD_TRANSACTION_TIME, 'MM') = '01'
                      
                UNION ALL
                
                SELECT CARD_TRANSACTION_TIME, CARD_TRANSACTION_AMOUNT, CARD_TRANSACTION_CONTENT, INDUSTRY_CODE
                 FROM OPEN_CARD_TRANSACTION_TEST01     
                 WHERE RESI_NUM = '9203101937988'
                      AND TO_CHAR(CARD_TRANSACTION_TIME, 'YYYY') = '2020' 
                      AND TO_CHAR(CARD_TRANSACTION_TIME, 'MM') = '01'    
                      AND MEANS IN('cardOne', 'cardTwo')
                )
SELECT SUBQUERY1.RESULT AS TYPE1, SUBQUERY2.RESULT AS "TYPE2", SUBQUERY3.RESULT AS "TYPE3", SUBQUERY4.RESULT AS "TYPE4",
        SUBQUERY5.RESULT AS "TYPE5", SUBQUERY6.RESULT AS "TYPE6", SUBQUERY7.RESULT AS "TYPE7", SUBQUERY8.RESULT AS "TYPE8"
FROM (SELECT * 
       FROM (SELECT SUM(RESULT) AS RESULT
             FROM(
                    SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
                    FROM WHOLE
                    GROUP BY INDUSTRY_CODE
                    HAVING INDUSTRY_CODE IN('I1', 'I2')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL))
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY1,
      
(SELECT * 
       FROM (SELECT SUM(RESULT) AS RESULT
             FROM(
                    SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
                    FROM WHOLE
                    GROUP BY INDUSTRY_CODE
                    HAVING INDUSTRY_CODE IN('I4', 'I5', 'I6')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL))
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY2,
      
     (SELECT * 
       FROM (SELECT SUM(RESULT) AS RESULT
             FROM(
                    SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
                    FROM WHOLE
                    GROUP BY INDUSTRY_CODE
                    HAVING INDUSTRY_CODE IN('I7', 'I8')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL))
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY3,
      
     (SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I9')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY4,
      
     (SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I10')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY5,
      
     (SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I11')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY6,
      
     (SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I12')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY7,
      
     (SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I13')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY8
WHERE ROWNUM <=1;

【问题讨论】:

    标签: sql oracle query-performance


    【解决方案1】:

    我已经简化了查询,因为您对所有子查询都有相同的分组,我们可以只使用条件聚合而不是多个子查询。

    您能否检查一下,因为由于架构对象,我无法从语法上检查查询的有效性。

    with whole as 
     (
      select card_transaction_time, card_transaction_amount, card_transaction_content, industry_code
        from card_transaction_test01
       where card_num in (select card_num from card_contract_test01 where resi_num = '9203101937988')
         and extract(year from card_transaction_time) = 2020
         and extract(month from card_transaction_time) = 1
      union all
      select card_transaction_time, card_transaction_amount, card_transaction_content, industry_code
         from open_card_transaction_test01     
       where resi_num = '9203101937988'
         and extract(year from card_transaction_time) = 2020
         and extract(month from card_transaction_time) = 1
         and means in('cardOne', 'cardTwo')
     )
    select result1 as TYPE1
         , result2 as TYPE2
         , result3 as TYPE3
         , result4 as TYPE4
         , result5 as TYPE5
         , result6 as TYPE6
         , result7 as TYPE7
         , result8 as TYPE8
    from 
    (
      select sum(case when industry_code in ('I1', 'I2') then card_transaction_amount else 0 end) as result1
           , sum(case when industry_code in ('I4', 'I5', 'I6') then card_transaction_amount else 0 end) as result2
           , sum(case when industry_code in ('I7', 'I8') then card_transaction_amount else 0 end) as result3
           , sum(case when industry_code in ('I9') then card_transaction_amount else 0 end) as result4
           , sum(case when industry_code in ('I10') then card_transaction_amount else 0 end) as result5
           , sum(case when industry_code in ('I11') then card_transaction_amount else 0 end) as result6
           , sum(case when industry_code in ('I12') then card_transaction_amount else 0 end) as result7
           , sum(case when industry_code in ('I13') then card_transaction_amount else 0 end) as result8
        from whole
      group by industry_code
    );
    

    【讨论】:

    • 有多行。我想我可以解决它。非常感谢!
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