条件检查之间的Mysql中有多个条件？有没有办法优化这个查询？

Question

我正在开发报告生成应用程序，我正在根据用户操作使用 PHP 生成查询。现在我根据工作人员的经验查询细节，有多个选择选项的可能性。结果来自连接 5 个表和子查询，我的查询工作正常并获取准确的结果

第一个场景： 让工作人员拥有 15 到 20 年的工作经验

查询

SELECT sd.staff_ref_id AS staff_code,
       sd.sur,
       sd.staff_name AS Name,
       sq.degree AS Qualification,
       sd.designation,
       d.department_name,
       TIMESTAMPDIFF(MONTH, s.join_date, CURDATE()) AS rec_exp_months,
       sum(spe.years) AS p_exp_yrs,
       sum(spe.months) AS p_exp_months
FROM staff_details sd
LEFT JOIN
  (SELECT s.staff_id,
          group_concat(sq.degree) AS degree
   FROM staff_details s,
        staff_qualification sq
   WHERE s.staff_id = sq.staff_id
   GROUP BY sq.staff_id
   ORDER BY sq.row_num)sq ON sd.staff_id = sq.staff_id
LEFT JOIN staff_department s ON s.staff_id = sd.staff_id
LEFT JOIN department d ON d.department_id =s.depart_id
LEFT JOIN staff_previous_experience spe ON spe.staff_id = sd.staff_id
WHERE ((TIMESTAMPDIFF(MONTH,sd.join_date,CURDATE())) +
           (SELECT (sum(sqn.years)*12) + sum(sqn.months)
            FROM staff_previous_experience sqn
            WHERE sqn.staff_id=sd.staff_id
            GROUP BY sqn.staff_id) BETWEEN 120 AND 180)
GROUP BY staff_ref_id,
         sd.sur,
         sd.staff_name,
         sd.designation,
         d.department_name,
         sq.degree,
         s.join_date

第二种情况：让工作人员的总经验介于 10 到 15 年和 15 到 20 年之间

查询

SELECT sd.staff_ref_id AS staff_code,
       sd.sur,
       sd.staff_name AS Name,
       sq.degree AS Qualification,
       sd.designation,
       d.department_name,
       TIMESTAMPDIFF(MONTH, s.join_date, CURDATE()) AS rec_exp_months,
       sum(spe.years) AS p_exp_yrs,
       sum(spe.months) AS p_exp_months
FROM staff_details sd
LEFT JOIN
  (SELECT s.staff_id,
          group_concat(sq.degree) AS degree
   FROM staff_details s,
        staff_qualification sq
   WHERE s.staff_id = sq.staff_id
   GROUP BY sq.staff_id
   ORDER BY sq.row_num)sq ON sd.staff_id = sq.staff_id
LEFT JOIN staff_department s ON s.staff_id = sd.staff_id
LEFT JOIN department d ON d.department_id =s.depart_id
LEFT JOIN staff_previous_experience spe ON spe.staff_id = sd.staff_id
WHERE ((TIMESTAMPDIFF(MONTH,sd.join_date,CURDATE())) +
           (SELECT (sum(sqn.years)*12) + sum(sqn.months)
            FROM staff_previous_experience sqn
            WHERE sqn.staff_id=sd.staff_id
            GROUP BY sqn.staff_id) BETWEEN 120 AND 180
         OR (TIMESTAMPDIFF(MONTH,sd.join_date,CURDATE())) +
           (SELECT (sum(sqn.years)*12) + sum(sqn.months)
            FROM staff_previous_experience sqn
            WHERE sqn.staff_id=sd.staff_id
            GROUP BY sqn.staff_id) BETWEEN 180 AND 240)
GROUP BY staff_ref_id,
         sd.sur,
         sd.staff_name,
         sd.designation,
         d.department_name,
         sq.degree,
         s.join_date

注意：以上突出显示的区域，我正在检查总经验，我正在将数据库中的输入和结果转换为月份并检查条件

问题：变暗区域是从 php 生成的查询，我使用 between 查询..根据从经验字段中选择了多少选项，between 查询会自动生成..
有没有办法优化这个..？
在查询中是否有一个选项可以在选项之间使用...？

我的查询执行时间是 0.0663 秒

等待回复、建议和建议 提前致谢

Answer 1

感觉这样会给你和第一个WHERE一样的效果：

WHERE sd.join_date >= CURDATE() - INTERVAL 180 MONTH
  AND sd.join_date  < CURDATE() - INTERVAL 120 MONTH

还有INDEX(join_date)。

如果是这样，那么它就简单多了，必须更快。

突出显示的子查询中的GROUP BY 是不必要的。

ORDER BY row_num 可能由于GROUP BY 而无效并被忽略。

LEFT JOIN 之后的派生表中似乎不需要 s。

为什么要分别计算BETWEEN 120 AND 180 和BETWEEN 180 AND 240？好像它们可以合并在一起。

如果不是更快，那么在 cmets 中进行我建议的清理工作，然后重新开始。请为每张桌子提供SHOW CREATE TABLE。