你如何忽略php搜索栏中的破折号和逗号

Question

目前，在我的搜索栏中，如果我完全按照输入数据库的方式输入城市名称，我就能找到它。例如：Nuits-Saint-Georges 或北卡罗来纳州达勒姆。

我希望我的用户能够输入 Nuits Saint Georges 或 Durham NC。

城市位于“位置”。

function Wo_GetAllJobs($filter_data = array()) {
global $wo, $sqlConnect;
$data = array();
$query_one = " SELECT * FROM " . T_JOB . " WHERE status = '1'";
if (!empty($filter_data['c_id'])) {
$category = $filter_data['c_id'];
$query_one .= " AND `category` = '{$category}'";
}
if (!empty($filter_data['after_id'])) {
if (is_numeric($filter_data['after_id'])) {
$after_id = Wo_Secure($filter_data['after_id']);
$query_one .= " AND `id` < '{$after_id}' AND `id` <> $after_id";
}
}
if (!empty($filter_data['keyword'])) {
$keyword = Wo_Secure($filter_data['keyword']);
$query_one .= " AND (`title` LIKE '%{$keyword}%' OR `location` LIKE 
'%{$keyword}%') ";
}
if (!empty($filter_data['user_id'])) {
$user_id = Wo_Secure($filter_data['user_id']);
$query_one .= " AND `user_id` = '{$user_id}'";
}
if (!empty($filter_data['type'])) {
$type = Wo_Secure($filter_data['type']);
$query_one .= " AND `job_type` = '{$type}'";
}

if (!empty($filter_data['length'])) {
$user_lat = $wo['user']['lat'];
$user_lng = $wo['user']['lng'];
$unit = 6371;
$query_one = " AND status = '1'";
$distance = Wo_Secure($filter_data['length']);
if (!empty($filter_data['c_id'])) {
$category = $filter_data['c_id'];
$query_one .= " AND `category` = '{$category}'";
}
if (!empty($filter_data['after_id'])) {
if (is_numeric($filter_data['after_id'])) {
$after_id = Wo_Secure($filter_data['after_id']);
$query_one .= " AND `id` < '{$after_id}' AND `id` <> $after_id";
}
}
if (!empty($filter_data['keyword'])) {
$keyword = Wo_Secure($filter_data['keyword']);
$query_one .= " AND (`title` LIKE '%{$keyword}%' OR `location` LIKE 
'%{$keyword}%') ";
}
if (!empty($filter_data['user_id'])) {
$user_id = Wo_Secure($filter_data['user_id']);
$query_one .= " AND `user_id` = '{$user_id}'";
}

if (!empty($filter_data['type'])) {
$type = Wo_Secure($filter_data['type']);
$query_one .= " AND `job_type` = '{$type}'";
}

Answer 1

用空格分割你的关键字，然后用%将它们内爆

//TODO query_one
//$query_one .= " AND (`title` LIKE ? OR `location` LIKE ?) ";
$stmt = $mysqli->prepare($query_one);
$keyWord = "%" . implode("%", explode(" ", $keyword)) . "%";
$stmt->bind_param("s", $keyWord));
$stmt->bind_param("s", $keyWord));
$stmt->execute();

请记住，准备好的语句是必须并且易于switch to

注意：

在关键字开头使用%会使优化器无法使用该列上的索引，如果有的话，所以如果你的数据量很大并且你开始遇到性能问题，你可以去到全文搜索（FTS）检查this

不用担心 MySQL 上的区分大小写比较

而关于MySQL会进行比较的情况，我会引用手册"Case Sensitivity in String Searches"

对于非二进制字符串（CHAR、VARCHAR、TEXT），字符串搜索使用 比较操作数的排序规则。对于二进制字符串（BINARY， VARBINARY, BLOB)，比较使用中字节的数值 操作数；这意味着对于字母字符，比较 将区分大小写。

..

默认字符集和排序规则为 utf8mb4 和 utf8mb4_0900_ai_ci，所以默认情况下非二进制字符串比较不区分大小写。

Answer 2

这就是我最终解决此问题的方法。

if (!empty($filter_data['keyword'])) {
    $keyword = $filter_data['keyword'];
    $keywordSearch = Wo_Secure(str_replace(',','',str_replace('-','',str_replace('.','',str_replace(' ', "", $keyword)))));
    $keyword = Wo_Secure($keyword);
    $query_one .= " AND (`title` LIKE '%{$keyword}%' OR REPLACE(REPLACE(REPLACE(REPLACE(`location`,' ',''),'-',''),'.',''),',','')LIKE '%{$keywordSearch}%') ";
}