【发布时间】:2018-08-08 13:47:31
【问题描述】:
向社区致以问候,
我整天都在努力寻找解决以下问题的方法。
场景如下,我有一张桌子
---TABLE_ONE---
INT ID
VARCHAR NAME
PRIMARY_KEY (ID)
我的另一个表由三列组成,它们共同组成一个复合键
---TABLE_TWO---
INT TABLE_ONE_ID (FK -> TABLE_ONE.ID)
VARCHAR NAME
VARCHAR EMAIL
PRIMARY_KEY(TABLE_ONE_ID, NAME, EMAIL)
我想要实现的关系是TABLE_ONE 实体将
拥有来自TABLE_TWO 的对象列表(一对多关系)。
我尝试这样做,如下所示。
@Entity
@Table(name = "TABLE_ONE")
public class TableOne {
@Column(name="id")
private int id;
@Column(name="name")
private String name
@OneToMany(fetch = FetchType.EAGER, mappedBy = "tableOne")
private List<TableTwo> tableTwoList;
//getters, setters, constructors
}
@Entity
@Table(name = "TABLE_TWO")
public class TableTwo {
@EmbeddedId
private TableTwoCompositeId tableTwoCompositeId;
@ManyToOne
@JoinColumn(name = "TABLE_ONE_ID", referencedColumnName = "ID", insertable = false, updatable = false)
private TableOne tableOne;
//getters, setters, constructors
}
@Embeddable
public class TableTwoCompositeId {
@Column(name = "TABLE_ONE_ID")
public Integer provider;
@Column(name = "NAME")
public String name;
@Column(name = "EMAIL")
public String email;
//getters, setters, constructors
}
但是,当从数据库中检索 TableOne 对象时,我得到了 javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not extract ResultSet 和 Caused by: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist。
提前感谢您的帮助!
【问题讨论】:
标签: java hibernate jpa one-to-many hibernate-onetomany