WHERE ',' + Manager + ',' LIKE '%,Jim,%'
或者我想匹配你的实际代码:
WHERE ',' + Manager + ',' LIKE '%,' + @Manager + ',%'
请注意,您的设计存在极大缺陷。根本没有理由将名称存储在此表中,更不用说任何数据点的逗号分隔列表。这些事实本身就很重要,所以要这样对待它们!
CREATE TABLE dbo.Managers
(
ManagerID INT PRIMARY KEY,
Name NVARCHAR(64) NOT NULL UNIQUE, ...
);
CREATE TABLE dbo.Projects
(
ProjectID INT PRIMARY KEY,
Name NVARCHAR(64) NOT NULL UNIQUE, ...
);
CREATE TABLE dbo.ProjectManagers
(
ProjectID INT NOT NULL FOREIGN KEY REFERENCES dbo.Projects(ProjectID),
ManagerID INT NOT NULL FOREIGN KEY REFERENCES dbo.Managers(ManagerID)
);
现在设置您提到的示例数据:
INSERT dbo.Managers(ManagerID, Name)
VALUES(1,N'John'),(2,N'Jim'),(3,N'Julie');
INSERT dbo.Projects(ProjectID, Name)
VALUES(1,N'Project 1'),(2,N'Project 2');
INSERT dbo.ProjectManagers(ProjectID,ManagerID)
VALUES(1,1),(1,2),(2,2),(2,3);
现在查找 Jim 管理的所有项目:
DECLARE @Manager NVARCHAR(32) = N'Jim';
SELECT p.ProjectID, p.Name
FROM dbo.Projects AS p
INNER JOIN dbo.ProjectManagers AS pm
ON p.ProjectID = pm.ProjectID
INNER JOIN dbo.Managers AS m
ON pm.ManagerID = m.ManagerID
WHERE m.name = @Manager;
或者你甚至可以手动短路一下:
DECLARE @Manager NVARCHAR(32) = N'Jim';
DECLARE @ManagerID INT;
SELECT @ManagerID = ManagerID
FROM dbo.Managers
WHERE Name = @Manager;
SELECT p.ProjectID, p.Name
FROM dbo.Projects AS p
INNER JOIN dbo.ProjectManagers AS pm
ON p.ProjectID = pm.ProjectID
WHERE pm.ManagerID = @ManagerID;
甚至更多:
DECLARE @Manager NVARCHAR(32) = N'Jim';
DECLARE @ManagerID INT;
SELECT @ManagerID = ManagerID
FROM dbo.Managers
WHERE Name = @Manager;
SELECT ProjectID, Name
FROM dbo.Projects AS p
WHERE EXISTS
(
SELECT 1
FROM dbo.ProjectManagers AS pm
WHERE pm.ProjectID = p.ProjectID
AND pm.ManagerID = @ManagerID
);
顺便说一句,我真的,真的,真的希望您原始查询中的DISTINCT 是不必要的。您真的有多个项目具有相同的名称和 ID?