原因：java.lang.NumberFormatException: Invalid double: "" with blank value

Question

当JSON 字符串有一些空白值时，我得到了错误，从服务器获取， 如何处理空白值 这是 JSON

{  
   "status":"success",
   "data":[  
      {  
         "id":"1",
         "name":"ABC",
         "address":"ABC, QWE",
         "lat":"16.799999",
         "lng":"96.150002",
         "admin_id":"4",
         "is_approved":"1",
         "added":"2015-08-07 11:17:12",
         "status":"1",
         "image_file":"",
         "image_width":"",
         "image_height":""
      }
   ]
}

Gson gson = new GsonBuilder().serializeNulls().create();
Type listType = new TypeToken<List<MyData>>() {}.getType();
myDataArrayList = gson.fromJson(response.getString("data"), listType);

在 MyData 类中，我尝试更改 lat, long 类型 int 并更改 json 中的值，但仍然显示相同的错误

public class MyData implements Parcelable {

    public int id;

    public String name;

    public String address;

    public String lat;

    public String lng;

    public String added;

    public int status;

    public String image_file;

    public int image_width;

    public int image_height;

}

在这一行显示错误

myDataArrayList = gson.fromJson(response.getString("data"), listType);

Answer 1

在MyData类中将image_width和image_height的类型改为String

public String image_width;

public String image_height;

由于int不能存储""这个字符串，在使用的时候可以解析成int。

Answer 2

public int image_width;     // Expected integer value while parsing 

public int image_height;   // Expected integer value while parsing

正如您在下面看到的，您有字符串字段。将低于 vale 的值初始化为 0

"image_width":0,
"image_height":0