BQ中STRUCT的聚合答案

【问题标题】：Aggregation over STRUCT in BQBQ中STRUCT的聚合
【发布时间】：2017-08-28 14:20:19
【问题描述】：

当我运行以下查询时

WITH total_count AS (
  SELECT
    id,
    pid,
    click_ts,
    stacked ,
    SUM(stacked) OVER (PARTITION BY id, pid) AS total_count
  FROM limited_count),   
stacked AS (
  SELECT *
  FROM total_count
  WHERE stacked > 1
)

SELECT
  id,
  pid,
  total_count,
  SUM(stacked) AS stacked 
FROM stacked
GROUP BY 1, 2, 3

我收到一个错误：

没有与参数类型的聚合函数 SUM 匹配的签名：STRUCT。支持的签名：总和（INT64）； SUM(FLOAT64) 在 [21:47]

当我尝试对以下视图进行 SUM(stacked) 时：

WITH total_count AS (
  SELECT
    id,
    pid,
    click_ts,
    stacked ,
    SUM(stacked) OVER (PARTITION BY id, pid) AS total_count
  FROM limited_count), 

SELECT *
FROM total_count
WHERE stacked > 1

一切正常！任何想法如何在同一个查询中进行？

【问题讨论】：

嗨，hamsy，请在提出问题时尝试正确格式化您的查询，以便于阅读。越容易阅读你的问题，你就越有可能得到答案:)

标签： sql google-bigquery

【解决方案1】：

#standardSQL
WITH total_count AS (
  SELECT id, pid, click_ts, stacked ,
  SUM(stacked) OVER (PARTITION BY id, pid) AS total_count
  FROM limited_count), 
stacked AS (
  SELECT *
  FROM total_count
  WHERE stacked > 1 ) 
SELECT id, pid, total_count, SUM(stacked.stacked) AS stacked 
FROM stacked
GROUP BY 1,2, 3

【讨论】：

它只是给了我记录的数量，而不是列中值的总和
太棒了！工作！非常感谢！