如何创建 SQL 运算符组合，如 ALL IN，NOT ALL IN答案

【问题标题】：How to create SQL Operators Combination like ALL IN, NOT ALL IN如何创建 SQL 运算符组合，如 ALL IN，NOT ALL IN
【发布时间】：2011-05-16 03:18:28
【问题描述】：

我在 Filter 类中有以下 4 个属性。我将解析以下 4 个属性到 StoredProcedure 并获得过滤后的结果。

/// <summary>
/// Gets and sets comma seperated condition ids.
/// Patients must have all these conditions in order to satisfy the filter.
/// </summary>
public string MustHaveAllConditions { get; set; }

/// <summary>
/// Gets and sets comma separated condition ids.
/// Patients must not have all of these conditions in order to satisfy the filter.
/// </summary>
public string MustNotHaveAllConditions { get; set; }

/// <summary>
/// Gets and sets comma separated condition ids.
/// Patients must have at least one of these conditions in order to satisfy the filter.
/// </summary>
public string MustHaveAtLeastOneCondition { get; set; }

/// <summary>
/// Gets and sets comma separated condition ids.
/// Patients must not have at least one of these conditions in order to satisfy the filter.
/// </summary>
public string MustNotHaveAtLeastOneCondition { get; set; }

我的存储过程将有四个参数，如下所示。例如：

@*MustHaveAll*Conditions = "1,2"

@*MustNotHaveAll*Conditions = "3,4"

@*MustHaveAtLeastOne*Condition = "5,6,7,8"

@*MustNotHaveAtLeastOne*Condition = "9, 10"

我正在使用一个 UDF，它返回一个带有 Ids 列的表。

我的问题：

基本上我可以使用 SQL“IN”运算符来查找具有至少一个 Condition 的患者（即：@MustHaveAtLeastOneCondition）和“NOT IN”运算符组合来过滤 @MustNotHaveAnyConditions。

是否有任何 SQL 运算符（或其他方法）来过滤 MustHaveAllConditions、MustNotHaveAllConditions 参数？

【问题讨论】：

标签： sql sql-server-2008 stored-procedures user-defined-functions

【解决方案1】：

-- Patients
declare @Patient table (PatientID int)

-- Conditions per patient
declare @PatientCondition table (PatientID int, ConditionID int)

-- Conditions table generated from param string
declare @Condition table (ConditionID int)

-- Test data
insert into @Patient
select 1 union all
select 2 union all
select 3

insert into @PatientCondition
select 1, 1 union all
select 1, 2 union all
select 1, 3 union all
select 2, 1 union all
select 3, 3

insert into @Condition
select 1 union all
select 2


-- MustHaveAll
select *
from @Patient as P
where P.PatientID in 
  (
    select PC.PatientID
    from @PatientCondition as PC
      inner join @Condition as C
        on PC.ConditionID = C.ConditionID
    group by PC.PatientID
    having count(PC.ConditionID) = (select count(ConditionID) from @Condition)
  )

--MustNotHaveAll
select *
from @Patient as P
where P.PatientID not in 
  (
    select PC.PatientID
    from @PatientCondition as PC
      inner join @Condition as C
        on PC.ConditionID = C.ConditionID
    group by PC.PatientID
    having count(PC.ConditionID) = (select count(ConditionID) from @Condition)
  )

-- MustHaveAtLeastOne
select *
from @Patient as P
where P.PatientID in
  (
    select PC.PatientID
    from @PatientCondition as PC
      left outer join @Condition as C
        on PC.ConditionID = C.ConditionID
    where C.ConditionID is not null
  )

--MustNotHaveAtLeastOne
select *
from @Patient as P
where P.PatientID not in
  (
    select PC.PatientID
    from @PatientCondition as PC
      left outer join @Condition as C
        on PC.ConditionID = C.ConditionID
    where C.ConditionID is not null
  )

【讨论】：

这太棒了。如果我想在一个 sql 查询中合并这四个条件以获得最终的患者列表，你能告诉我最有效的方法吗？
@CharithJ – 您可以将不同查询中的 where 子句添加到一个查询中，并用 and 分隔。 where PatientID in (...) and PatientID in (...) and ...等

【解决方案2】：

确实没有一种简单的方法可以完成您所描述的操作。我会做的可能是把你的字符串拆分成一个表变量，然后使用右、左和内连接的组合从另一个表变量中删除结果，这是我的输出。

【讨论】：