【发布时间】:2018-01-30 06:37:00
【问题描述】:
我无法理解以下链接中提到的 select UDF 语句:
How to split a comma-separated value to columns
CREATE FUNCTION dbo.Split (
@InputString VARCHAR(500),
@Delimiter VARCHAR(1)
)
RETURNS @Items TABLE (
Item VARCHAR(500)
)
AS
BEGIN
IF @Delimiter = ' '
BEGIN
SET @Delimiter = ','
SET @InputString = REPLACE(@InputString, ' ', @Delimiter)
END
IF (@Delimiter IS NULL OR @Delimiter = '')
SET @Delimiter = ','
--INSERT INTO @Items VALUES (@Delimiter) -- Diagnostic
--INSERT INTO @Items VALUES (@InputString) -- Diagnostic
DECLARE @Item VARCHAR(500)
DECLARE @ItemList VARCHAR(500)
DECLARE @DelimIndex INT
SET @ItemList = @InputString
SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)
WHILE (@DelimIndex != 0)
BEGIN
SET @Item = SUBSTRING(@ItemList, 0, @DelimIndex)
INSERT INTO @Items VALUES (@Item)
-- Set @ItemList = @ItemList minus one less item
SET @ItemList = SUBSTRING(@ItemList, @DelimIndex+1, LEN(@ItemList)-@DelimIndex)
SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)
END -- End WHILE
IF @Item IS NOT NULL -- At least one delimiter was encountered in @InputString
BEGIN
SET @Item = @ItemList
INSERT INTO @Items VALUES (@Item)
END
-- No delimiters were encountered in @InputString, so just return @InputString
ELSE INSERT INTO @Items VALUES (@InputString)
RETURN
END -- End Function
GO
我检查了权限,并确保该函数已使用正确的架构创建:
SELECT * FROM INFORMATION_SCHEMA.ROUTINES
但是,当我运行以下命令时遇到了问题:
select dbo.Split(TargetFolderId, ',') from ReportConfig where ReportId = 9
错误:
找不到“dbo”列或用户定义的函数,或者 聚合“dbo.Split”,或者名称不明确。
但我能做到
select * from dbo.Split('stringA,stringB', ',')
会不会是我们俩都用的SSMS版本的区别?
我正在使用 SQL2017 - SSMS v17.4。
【问题讨论】:
-
这是一个表值函数,它返回一个 TABLE 的结果。它必须用作像“Select * from ...”这样的表格
标签: sql sql-server select user-defined-functions