为每位员工获取所有信息？

Question

预期输出：

SL#  Emp#   Employee Name       IN                     OUT         
1    106    George Jacob 24/Sep/2017 8:08:00AM 24/Sep/2017 12:53:00PM 04:45:00
                         24/Sep/2017 2:13:00PM 24/Sep/2017 5:58:00PM 03:45:00
                         25/Sep/2017 8:12:00AM 25/Sep/2017 6:02:00PM 09:50:00
                         26/Sep/2017 8:18:00AM 26/Sep/2017 2:15:00PM 05:57:00
                         26/Sep/2017 2:32:00PM 26/Sep/2017 6:00:00PM 03:28:00
                         27/Sep/2017 8:02:00AM 27/Sep/2017 5:57:00PM 09:55:00
                         28/Sep/2017 8:01:00AM 28/Sep/2017 6:01:00PM 10:00:00
                         01/Oct/2017 8:16:00AM 01/Oct/2017 5:56:00PM 09:40:00
                         02/Oct/2017 7:58:00AM 02/Oct/2017 5:56:00PM

我试过这个查询，但没有得到上面提到的准确输出：

SELECT Row_number()
     OVER (ORDER BY A.dt ASC)                        AS SNo,
     CONVERT(DATE, A.dt)
   --CONVERT(VARCHAR(26), A.DT, 103)  as DATEEVENT, 
                                                 b.emp_code,
   B.emp_name,
   F.event_entry_name,
   a.dt,
   Cast(LEFT(CONVERT(TIME, a.dt), 5) AS VARCHAR) AS 'time',
   Isnull(B.areaname, 'OAE6080036073000006')     AS areaname,
   C.dept_name,
   b.emp_reader_id,
   Isnull(c.dept_name, '')                       AS group_name,
   CONVERT(CHAR(11), '2017/12/30', 103)          AS StartDate,
   CONVERT(CHAR(11), '2018/01/11', 103)          AS ToDate,
   0                                             AS emp_card_no
FROM   dbo.trnevents AS A
   LEFT OUTER JOIN dbo.employee AS B
                ON A.emp_reader_id = B.emp_reader_id
   LEFT OUTER JOIN dbo.departments AS C
                ON B.dept_id = C.dept_id
   LEFT OUTER JOIN dbo.devicepersonnelarea AS E
                ON A.pointid = E.areaid
   LEFT OUTER JOIN dbo.event_entry AS F
                ON A.eventid = F.event_entry_id  

Answer 1

您可以使用 subselect 或 CTE 来获取按员工排序的数据并将其用作主数据表。与此类似（必要时进行调整）：

;with ordered as (
select 
    emp_reader_id as empId,
    CONVERT(DATE, dt) as Punch,
    Row_number()
     OVER (PARTITION BY emp_reader_id ORDER BY CONVERT(DATE, dt) ASC) as OrderedPunch
from trnevents
)
SELECT 
    entered.empId, 
    entered.Punch as PunchIn,
    exited.Punch as PunchOut
from
    ordered as entered
    left join ordered as exited on 
        entered.empId = exited.empId
        and entered.OrderedPunch + 1 = exited.OrderedPunch

解释：“有序”CTE 确实显示了按日期排序的员工进入/退出。由于PARTITION BY，每个员工的ROW_NUMBER 都被重置（我假设emp_reader_id 确实包含员工ID）。

获得每个员工的计数器后，我将每个员工的每个打孔（左连接中的第一个条件）与该员工的下一个打孔（左连接中的第二个条件）连接起来。这样我就可以显示入口列和出口（下一拳）。

在您获得数据中的 in 和 out 列之后，您可能想要排除一些数据（每个员工的奇数行是您想要的行）添加 WHERE entered.OrderedPunch %2 = 1