【问题标题】:Table value function not returning results表值函数不返回结果
【发布时间】:2013-02-15 02:40:14
【问题描述】:

我的表值函数将返回空结果。我不确定我的表值函数的格式是否正确。

我已对所有变量进行硬编码并自行运行每个 select 语句,但我无法让表返回结果。

我还填写了一个表变量并选择了@Table_Var,这确实返回了正确的结果,所以它与我的代码结构方式有关。

所有语句都正常工作,我无法从函数返回数据。

有人马上就看到我做错了什么吗?

编辑

我已经把松散的代码移到了一个函数中,这样它就不会那么混乱了。

该功能正常工作,其他一切,当我尝试返回表格时接受。

--select * from  [dbo].[fn_Professionals_GetMiniUserInfo](null,'a9cec535-ac48-4197-b8a0-87702cb14e52') 
ALTER FUNCTION [dbo].[fn_NonPros_GetMiniUserInfo] 
(
 @NonProID  INT = NULL,
 @UserID UNIQUEIDENTIFIER = NULL
) 
RETURNS 
    @Table_Var TABLE 
(
    -- Add the column definitions for the TABLE variable here
    Avatar     NVARCHAR(50), 
    ID         int,
    FName      varchar(50),
    LName      varchar(50),
    Title      varchar(20),
    UserID     UNIQUEIDENTIFIER,
    CompanyID  INT,
    CoWorkers  INT,
    Street     varchar(60),
    City       varchar(30),
    StateCD    char(2),
    ZipCode    varchar(5),
    WorksFor   VARCHAR(30),
    Phone      VARCHAR(12),
    Email      NVARCHAR(256)
)
AS
BEGIN

INSERT INTO @Table_Var

SELECT
    (SELECT [AFCCInc_Com].[dbo].[aspnet_fn_GetProfileElement]('Avatar',ap.PropertyNames,ap.PropertyValuesString )FROM AFCCInc_Com.dbo.aspnet_Profile ap
                                                                                                                 WHERE ap.UserId = nonPro.UserID)as'Avatar',
            na.NonProID'ID',c.FirstName'FName',c.LastName'LName',c.Title,@UserID 'UserID',
            ci.CompanyID,ci.CoWorkers,a.AddressLine, cit.City,s.StateCD,z.ZIPCode,ci.CompanyName'WorksFor',
            p.Phone,
                  (SELECT Email FROM AFCCInc_Com.dbo.aspnet_Membership m WHERE m.UserId = nonPro.UserID)'Email'

                  FROM  NonPros.NonPros nonPro         with(nolock)                                   JOIN
                  NonPros.utbNonProsUtbAddresses    na with(nolock) on na.NonProID = nonPro.NonProID  JOIN
                  dbo.fn_GetCompanyInfo(@UserID)    ci              ON ci.UserID   = nonPro.UserID    JOIN
                  Person.utbAddresses                a with(nolock) ON a.AddressID = na.AddressID     JOIN
                  [Person].[UtbAddressesutbContact] ac with(nolock)on ac.AddressID = a.AddressID      JOIN
                  Person.utbContact                  c with(nolock)ON ac.ContactID = c.ContactID      JOIN
                  Person.utbContactUtbPhones        cp with(nolock)ON c.ContactID = cp.ContactID      JOIN
                  Person.utbPhones                   p with(nolock)ON p.PhoneID = cp.PhonesID         JOIN
                  Person.utbZipCodes                 z WITH(NOLOCK) ON z.ZipCodeID = a.ZipCodeID      JOIN
                  Person.utbCitys                  cit WITH(NOLOCK) ON cit.CityID  = z.CityID         JOIN
                  Person.utbStates                   s WITH(NOLOCK) ON s.StateCD = z.StateCD

                  WHERE c.ContactTypeID = 7/*me*/ 
                  AND p.PhoneTypeID = 6/*main*/
                  AND nonPro.UserID = 'a9cec535-ac48-4197-b8a0-87702cb14e52';
    RETURN 
    END;


    alter FUNCTION fn_GetCompanyInfo (@UserID UNIQUEIDENTIFIER)
RETURNS 
@Table_Var TABLE 
(
    UserID      UNIQUEIDENTIFIER,
    CompanyID   INT, 
    CompanyName VARCHAR(50),
    CoWorkers   INT
)
AS
BEGIN

    INSERT INTO @Table_Var

          SELECT @UserID,
                 p.ProfessionalID, 
                 p.ProfessionalName,
                (SELECT COUNT(NonProID)'CoWorkers' FROM BuildingPros.utbProfessionalsUtbNonPros with(nolock)WHERE ProfessionalID = p.ProfessionalID)

                                    FROM BuildingPros.utbProfessionalsUtbNonPros bp with(nolock)                                       JOIN
                                         BuildingPros.utbProfessionals            p with(nolock)ON p.ProfessionalID = bp.ProfessionalID

                      WHERE bp.NonProID = (SELECT NonProID FROM NonPros.NonPros where UserID = @UserID);
    RETURN 
END

【问题讨论】:

  • 你能告诉你在哪里使用你的参数吗? @NonProID INT = NULL, @UserID UNIQUEIDENTIFIER = NULL
  • 尝试将函数的内容拉出到查询窗口中。声明一个表变量以匹配函数定义,并声明变量以匹配函数输入。然后将变量设置为您正在使用的输入值。看看这是否有效。如果确实如此,则问题出在您的函数定义中。如果不是,则在您的查询中。使用查询窗口中的代码(不是函数),调试起来会容易得多。

标签: sql-server tsql function


【解决方案1】:

在我清理代码并将插入上方的选择移动到我的表变量中之后,一切正常。

我相信这部分是我的问题。

**(SELECT [AFCCInc_Com].[dbo].[aspnet_fn_GetProfileElement]('Avatar',ap.PropertyNames,ap.PropertyValuesString)),**

.

SELECT
    (SELECT [AFCCInc_Com].[dbo].[aspnet_fn_GetProfileElement]('Avatar',ap.PropertyNames,ap.PropertyValuesString)),
            na.NonProID'ID',c.FirstName'FName',c.LastName'LName',c.Title,'a9cec535-ac48-4197-b8a0-87702cb14e52' 'UserID',
            ci.CompanyID,ci.CoWorkers,a.AddressLine, cit.City,s.StateCD,z.ZIPCode,ci.CompanyName'WorksFor',
            p.Phone,
                  (SELECT Email FROM AFCCInc_Com.dbo.aspnet_Membership m WHERE m.UserId = nonPro.UserID)'Email'

                  FROM  
                  NonPros.NonPros nonPro                                                  JOIN
                  AFCCInc_Com.dbo.aspnet_Profile ap      ON ap.UserId =nonPro.UserID       JOIN
                  NonPros.utbNonProsUtbAddresses    na   ON na.NonProID = nonPro.NonProID  JOIN
                  dbo.fn_GetCompanyInfo('a9cec535-ac48-4197-b8a0-87702cb14e52')    ci   ON ci.UserID   = nonPro.UserID    JOIN
                  Person.utbAddresses                a   ON a.AddressID = na.AddressID     JOIN
                  [Person].[UtbAddressesutbContact] ac   ON ac.AddressID = a.AddressID     JOIN
                  Person.utbContact                  c   ON ac.ContactID = c.ContactID     JOIN
                  Person.utbContactUtbPhones        cp   ON c.ContactID = cp.ContactID    JOIN
                  Person.utbPhones                   p   ON p.PhoneID = cp.PhonesID       JOIN
                  Person.utbZipCodes                 z   ON z.ZipCodeID = a.ZipCodeID      JOIN
                  Person.utbCitys                  cit   ON cit.CityID  = z.CityID         JOIN
                  Person.utbStates                   s   ON s.StateCD = z.StateCD

                  WHERE c.ContactTypeID = 7/*me*/ 
                  AND p.PhoneTypeID = 6/*main*/
                  AND nonPro.UserID = 'a9cec535-ac48-4197-b8a0-87702cb14e52'
    RETURN 

【讨论】:

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