【问题标题】:Could not determine type for: java.util.Set, at table无法确定类型:java.util.Set,在表中
【发布时间】:2017-11-11 09:47:32
【问题描述】:

我创建了两个具有多对多关系的类,如下所示:

@Entity
@Table(name = FoodEntity.TABLE_NAME)
public class FoodEntity extends BaseEntity<Long> {

public static final String TABLE_NAME = "T_FOOD";

@ManyToMany
@JoinTable(
    name = "T_FOOD_FOODCATEGORY",
    joinColumns =       { @JoinColumn(name = "FOOD_ID") }, 
    inverseJoinColumns =    { @JoinColumn(name = "FOOD_CATEGORY_ID") })
private Set<FoodCategoryEntity> categories;

public Set<FoodCategoryEntity> getCategories() {
return categories;
}

public void setCategories(Set<FoodCategoryEntity> categories) {
this.categories = categories;
}

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "FOOD_ID", nullable = false)
@Override
public Long getId() {
return id;
}

@Override
public void setId(Long id) {
this.id = id;
}

}

和:

@Entity
@Table(name = FoodCategoryEntity.TABLE_NAME)
public class FoodCategoryEntity extends BaseEntity<Long> {

public static final String TABLE_NAME = "T_FOOD_CATEGORY";

@ManyToMany(mappedBy = "categories")
private Set<FoodEntity> foods;

public Set<FoodEntity> getFoods() {
return foods;
}

public void setFoods(Set<FoodEntity> foods) {
this.foods = foods;
}

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "FOOD_CATEGORY_ID", nullable = false)
@Override
public Long getId() {
return id;
}

@Override
public void setId(Long id) {
this.id = id;
}

}

但是当我用 junit、spring 和 hibernate 测试这种关系时,我得到以下异常:

Caused by: org.hibernate.MappingException: Could not determine type for: java.util.Set, at table: T_FOOD, for columns: [org.hibernate.mapping.Column(categories)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:455)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:422)
at org.hibernate.mapping.Property.isValid(Property.java:226)
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:597)
at org.hibernate.mapping.RootClass.validate(RootClass.java:265)
at org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:329)
at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:451)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:889)
... 46 more

我检查了注解包引用和所有 ID 列名,但它们都是正确的。 要点:我也使用HSQLDB数据库,它的存储位置是一个文件。

【问题讨论】:

标签: java hibernate jpa


【解决方案1】:

我发现了我的问题。 persistence.xml 中的映射类不正确。

【讨论】:

    【解决方案2】:

    您的注释推断属性访问类型映射,因为@Id 放置在 getter 上

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "FOOD_ID", nullable = false)
    @Override
    public Long getId() {
        return id;
    }
    

    但是集合注释放在字段级别

    @ManyToMany
    @JoinTable(
        name = "T_FOOD_FOODCATEGORY",
        joinColumns =       { @JoinColumn(name = "FOOD_ID") }, 
        inverseJoinColumns =    { @JoinColumn(name = "FOOD_CATEGORY_ID") })
    private Set<FoodCategoryEntity> categories;
    

    虽然(未)在 getter 上指定有效配置

    public Set<FoodCategoryEntity> getCategories() {
        return categories;
    }
    

    您不应混合使用两种类型的配置。

    【讨论】:

    • 当我将类别字段上的注释位置更改为方法时,我得到以下异常:原因:org.hibernate.AnnotationException:使用 OneToMany 或 ManyToMany 以未映射的类为目标:ir.msr.projects.crawler。 food.entity.FoodEntity.categories[ir.msr.projects.crawler.food.entity.FoodCategoryEntity]
    • 第二个不扫描。测试配置问题?
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