【发布时间】:2018-02-06 00:30:48
【问题描述】:
我正在尝试执行如下查询,通过 case 语句进行选择并按相同的 case 语句进行分组..
Select USER,
(CASE
WHEN value between 0 AND 2 then '0-2'
WHEN value between 3 AND 4 then '3-4'
ELSE '5+'
END) as CASE_STATEMENT ,
SUM(value)
.....
Group by user, CASE_STATEMENT
使用 JPA 2.0 Criteria API 和 Hibernate。
我的测试用例看起来像...
CriteriaBuilder cb = em.getCriteriaBuilder()
CriteriaQuery cq = cb.createQuery(Tuple)
def root = cq.from(TestEntity)
def userGet = root.get('user')
def valueGet = root.get('value')
def caseExpr =
cb.selectCase()
.when(cb.between(valueGet, 0, 2), '0-2')
.when(cb.between(valueGet, 3, 4), '3-4')
.otherwise('5+')
def sumExpr = cb.sum(valueGet)
cq.multiselect([userGet, caseExpr, sumExpr])
cq.groupBy([userGet, caseExpr])
log(typedQuery.unwrap(Query).queryString)
List<Tuple> tuples = typedQuery.getResultList()
queryString 的日志语句读取
SELECT generatedAlias0.USER,
CASE
WHEN generatedAlias0.value BETWEEN 0 AND 2 THEN Cast(:param0 AS STRING)
WHEN generatedAlias0.value BETWEEN 3 AND 4 THEN Cast(:param1 AS STRING)
ELSE Cast(:param2 AS STRING)
END,
Sum(generatedAlias0.value)
FROM test AS generatedAlias0
GROUP BY generatedAlias0.USER,
CASE
WHEN generatedAlias0.value BETWEEN 0 AND 2 THEN Cast(
:param3 AS STRING)
WHEN generatedAlias0.value BETWEEN 3 AND 4 THEN Cast(
:param4 AS STRING)
ELSE Cast(:param5 AS STRING)
END
在调用 typedQuery.getResultList() 时,我得到以下错误语句
javax.persistence.PersistenceException: org.hibernate.exception.GenericJDBCException: could not extract ResultSet
Caused by: org.h2.jdbc.JdbcSQLException: Column "TESTENTITY0_.VALUE" must be in the GROUP BY list; SQL statement:
select testentity0_.user as col_0_0_, case when testentity0_.value between 0 and 2 then cast(? as varchar(255)) when testentity0_.value between 3 and 4 then cast(? as varchar(255)) else cast(? as varchar(255)) end as col_1_0_, sum(testentity0_.value) as col_2_0_ from test testentity0_ group by testentity0_.user , case when testentity0_.value between 0 and 2 then cast(? as varchar(255)) when testentity0_.value between 3 and 4 then cast(? as varchar(255)) else cast(? as varchar(255)) end [90016-194]
我尝试按表达式分组的方式有问题吗?我还尝试按别名和数字文字 (1, 2) 进行分组
有没有其他方法可以构建 SQL 以获得相同的结果?
谢谢。
【问题讨论】:
-
现在看到同样的问题,找不到合适的解决方案。在问题中添加了一个赏金,希望有人会调查它并可以解释为什么案例中的列需要在 GROUP BY 中(因此,完全消除了计数的目的)。
-
直接在 H2 中运行完全相同的查询似乎成功了......所以它可能是一个 JPA 错误?
-
确定你在 SQL 中的问题,因为你有错误:
org.h2.jdbc.JdbcSQLException: Column "TESTENTITY0_.VALUE" must be in the GROUP BY list -
我相信这是因为您对案例语句进行了参数化。您可以尝试使用子查询吗?
select user, case_statement, sum(value) as sum_value from ( select user, (case when value between 0 and 2 then '0-2' when value between 3 and 4 then '3-4' else '5+' end) as case_statement , value from test ) as t1 group by user, case_statement -
作为@daggett 建议的替代方案,请尝试使用
cb.literal('0-2')、cb.literal('3-4')、cb.literal('5+')代替
标签: java hibernate jpa groovy criteria-api