【问题标题】:Is it possible to order a query by primary key?是否可以按主键排序查询?
【发布时间】:2014-05-07 19:23:18
【问题描述】:

我有一个包含UTCTime 类型字段的实体定义。

Foo
    time UTCTime
    ...

我想选择一系列按时间排序的实体。如果两个实体的时间相等,我不在乎哪个先到,我只希望每次的顺序都相同。实体键是唯一的,似乎按键排序是完美的 选择。

是否可以执行selectList 之类的查询并按主键对匹配的行进行排序? 或者

  • 是否可以在实体中包含主键?
  • 或者,有没有其他方法来确定行的顺序?

当然,我总是可以只请求按时间排序,然后自己按键排序返回的列表。但这排除了使用SelectOps OffsetByLimitTo,因为我无法事先知道会有多少相同时间的实体。

【问题讨论】:

  • 我不确定,但也许AscDesc SelectOps 可以用于此目的?
  • @chi 这些仅适用于实体值本身的字段,而不适用于键。

标签: haskell yesod persistent


【解决方案1】:

我不确定SelectOpts 是否仅适用于实体值,因此我在一小段代码中检查了这一点。假设一个实体如下所示:

EntityA
    key Text
    time UTCTime
    deriving Show

您可以只列出您感兴趣的SelectOpts 并获得理想的输出。

示例代码如下所示:

main :: IO ()
main = runSqlite ":memory:" $ do
    runMigration migrateAll

    currentTime <- liftIO getCurrentTime

    -- insert some data
    _ <- insert $ EntityA "first" currentTime
    _ <- insert $ EntityA "second" currentTime
    _ <- insert $ EntityA "third" currentTime
    _ <- insert $ EntityA "fourth" currentTime

    currentTime <- liftIO getCurrentTime

    -- insert more data
    _ <- insert $ EntityA "fifth" currentTime
    _ <- insert $ EntityA "sixth" currentTime
    _ <- insert $ EntityA "seventh" currentTime
    _ <- insert $ EntityA "eighth" currentTime

    currentTime <- liftIO getCurrentTime

    -- insert more data
    _ <- insert $ EntityA "this one will be first" currentTime

    sorted <- selectList [] [Desc EntityATime, Asc EntityAId]
    mapM_ (liftIO . print) sorted

输出是:

Migrating: CREATE TABLE "entity_a"("id" INTEGER PRIMARY KEY,"key" VARCHAR NOT NULL,"time" TIMESTAMP NOT NULL)
Entity {entityKey = Key {unKey = PersistInt64 9}, entityVal = EntityA {entityAKey = "this one will be first", entityATime = 2014-05-07 20:15:35.627561 UTC}}
Entity {entityKey = Key {unKey = PersistInt64 5}, entityVal = EntityA {entityAKey = "fifth", entityATime = 2014-05-07 20:15:35.627026 UTC}}
Entity {entityKey = Key {unKey = PersistInt64 6}, entityVal = EntityA {entityAKey = "sixth", entityATime = 2014-05-07 20:15:35.627026 UTC}}
Entity {entityKey = Key {unKey = PersistInt64 7}, entityVal = EntityA {entityAKey = "seventh", entityATime = 2014-05-07 20:15:35.627026 UTC}}
Entity {entityKey = Key {unKey = PersistInt64 8}, entityVal = EntityA {entityAKey = "eighth", entityATime = 2014-05-07 20:15:35.627026 UTC}}
Entity {entityKey = Key {unKey = PersistInt64 1}, entityVal = EntityA {entityAKey = "first", entityATime = 2014-05-07 20:15:35.626622 UTC}}
Entity {entityKey = Key {unKey = PersistInt64 2}, entityVal = EntityA {entityAKey = "second", entityATime = 2014-05-07 20:15:35.626622 UTC}}
Entity {entityKey = Key {unKey = PersistInt64 3}, entityVal = EntityA {entityAKey = "third", entityATime = 2014-05-07 20:15:35.626622 UTC}}
Entity {entityKey = Key {unKey = PersistInt64 4}, entityVal = EntityA {entityAKey = "fourth", entityATime = 2014-05-07 20:15:35.626622 UTC}}

如果您有兴趣,我可以发布示例项目(位于fpcomplete.com),但我想这很好地说明了这一点。

【讨论】:

  • 老实说,我从来没有想过要这样做。我一直认为 key 和 value 是完全分开的。非常感谢!
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