具有相同项目 ID 的 SQL 分组问题

Question

我正在尝试跟踪销售代表的总销售额以及他上班的时间。

我有以下两张表：

表1：

employeeID | item  |  price  |  timeID  
----------------------------------------
1          |   1   |   12.92 |   123     
1          |   2   |   10.00 |   123     
1          |   2   |   10.00 |   456     

表2：

ID  |  minutes_in_shift
--------------------------
123     |   45
456     |   15

我将使用以下 SQL 连接这两个查询：

SELECT
  t1.employeeID, t1.item, t1.price, t1.shiftID, t2.minutes_in_shift
FROM table1 t1
JOIN table 2 t2 ON (t2.ID = t1.timeID)

这将返回下表：

employeeID | item  |  price  |  timeID  |   minutes_in_shift
---------------------------------------------------
1          |   1   |   12.92 |   123    |   45  
1          |   2   |   10.00 |   123    |   45
1          |   2   |   10.00 |   456    |   15

但是，我希望合并结果有这样的结果：

employeeID  |   itemsSold   |  priceTotals   |    totaltimeworked
-----------------------------------------------------------------
  1         |      3        |    32.92       |       60

我可以将 COUNT 和 SUM 用于项目和价格，但我无法弄清楚如何以上面显示的方式正确显示总工作时间。 注意：我只是在计算工作时间时遇到了麻烦。在 123 班 - 员工 1 工作 45 分钟，不管他卖了多少物品。

有什么建议吗？

Answer 1

如果您希望按原样使用样本数据，则需要提取班次并对分钟求和，如下所示：

with a as (
  select employeeID, count(*) itemsSold, sum(price) priceTotals  
  from Sampletable1 
  group by employeeID),
b as (
  select employeeID, shiftID, max(minutes_in_shift) minutes_in_shift
  from Sampletable1
  group by employeeID, shiftID),
c as (
  select employeeID, sum(minutes_in_shift) totaltimeworked
  from b
  group by employeeID)
select a.employeeID, a.itemsSold, a.priceTotals, c.totaltimeworked
from a inner join c on a.employeeID = c.employeeID

但是，对于您现有的表，选择语句会容易得多：

with a as (
  select employeeID, timeID, count(*) itemsSold, sum(price) priceTotals  
  from table1 
  group by employeeID, timeID)
select a.employeeID, sum(a.itemsSold), sum(a.priceTotals), sum(table2.minutes_in_shift) totaltimeworked
from a inner join table2 on a.timeID = table2.ID
group by a.employeeID

Answer 2

我认为这个查询应该做你想做的事：

SELECT t1.employeeID,
       count(t1.item)                    AS itemsSold,
       sum(t1.price)                     AS priceTotals,
       sum(DISTINCT t2.minutes_in_shift) AS totaltimeworked
  FROM table1 t1
  JOIN table2 t2 ON (t2.ID = t1.timeID)
 GROUP BY t1.employeeID;

Check on SQL Fiddle