按具有起点和终点 SQL Server 的动态间隔分组

Question

我有一个表，其中包含一个列 DED，其中的数字可以从 0 到无穷大。我有兴趣将它们从 0 开始分组（上限为开区间，下限为闭区间）并获得百分比总计

假设我有一列

DED     AMT
0.0004   4
0.0009   1
0.001    2
0.002    1
0.009    4
0.01     5
0.04     6
0.09     3
0.095    1
0.9      3
1        2
100      1
500      1 

所以我想要以下间隔：

DED       AMT    PAMT
0-0.01     12    0.3529
0.01-0.02  5     0.1470
0.04-0.05  6     0.1764
0.09-0.1   4     0.1176
0.9-1      3     0.0882
1          2     0.0588

我试过了：

SELECT CAST(DED/.02*.02 AS VARCHAR) +' - '+CAST(DED/.02*.02 +.01 AS VARCHAR)  AS DED, 
SUM(AMT) AS AMT,ISNULL(SUM(AMT)*1.000/NULLIF(SUM(SUM(AMT)) OVER (),0),0) AS PAMT 
FROM MYTABLE 
   WHERE DED/.02*.02<=1 
   GROUP BY DED/.02*.02

感谢您的帮助

Answer 1

SELECT
  ROUND(DED, 2, 1)          AS DED_lower,
  ROUND(DED, 2, 1) + 0.01   AS DED_upper,
  SUM(AMT)                  AS SUM_AMT, 
  SUM(AMT) * 1.0
  /
  SUM(AMT) OVER ()          AS PAMT
FROM
  mytable
WHERE
  DED <= 1
GROUP BY
  ROUND(DED, 2, 1)

ROUND(DED, 2, 1) 将向下舍入到小数点后两位。给出大小为 0.01 的相同大小的带。

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