MYSQL SUM() 返回前 10 个值

Question

我正在尝试查找 7 个数字字段的总和以找到总数，结合输出以显示 LIMIT 10 个结果 ORDER BY total of each SUM。

这是我的 SUM 代码，它可以独立运行，但我不确定如何同时使用这两个查询，不断出现语法错误。

SUM(comfort + service + ambience + friendliness + spacious + experience + toilets)/(7)/COUNT(shop_id) AS total FROM ratings GROUP BY shop_id

这是我正常返回数据的SQL查询：

SELECT * FROM pubs, services, ratings
WHERE pubs.shop_id=services.shop_id AND pubs.shop_id=ratings.shop_id
GROUP BY shop_name
ORDER BY shop_name ASC

我的数据库中没有存储 7 个值的总数，我使用上面的 SUM 查询来查找总数。谢谢

Answer 1

尝试使用

SELECT pubs.*, services.*, sum(temp.total) as final_total FROM pubs inner join services on pubs.shop_id=services.shop_id
inner join (
select 
SUM(comfort + service + ambience + friendliness + spacious + experience + toilets)/(7) /COUNT(shop_id) AS total, shop_id FROM ratings GROUP BY shop_id
) as temp on pubs.shop_id=temp.shop_id
GROUP BY shop_name
ORDER BY final_total DESC, shop_name ASC