按 2 列 SQL Server 分区

Question

我参加了我之前的一个练习并增加了一些复杂性。 你可以在下面找到我原来的问题：select case with "over partition by"

场景：（使用 SQL Server 2012）

 create table #testing (b varchar (20), a date, c int, e int)

 insert into #testing (b,a,c,e)
 values
    ('xf_1m','2015-03-02','1','3'),
    ('xf_3m','2015-03-02','2','5'),
    ('xf_5y','2015-03-02','4','2'),
    ('xf_10y','2015-03-02','3','6'),
    ('ay_10y','2015-03-02','7','2'),
    ('adfe_1m','2015-03-02','2','5'),
    ('xm_1m','2013-02-01','7','2'),
    ('xf_15y','2013-02-01','1','8'),
    ('xf_20y','2013-02-01','10','1')

使用此查询后：

select
    b, a, c, e,
    substring (b, 1, CHARINDEX ('_', b) - 1) rnc,
    substring(b, CHARINDEX('_', b) + 1, LEN (b)) rnb,
    case 
        when b like 'xf%' then -- 
            (sum(c * e) over (partition by a )) end as sumProduct
into #testing2
from #testing

select 
    *,
    case 
        when b like 'xf%' then -- 
        (sum(c * e) over (partition by a )) end as sumProduct
into #testing3
from #testing2

select * 
from #testing3

我得到了这个：

现在我想计算由 rnc 和日期（a 列）分区的 sumProduct。 这该怎么做？我尝试使用 group by，但我遇到了来自 select 的不相等数字和我分组依据的项目数的问题。

所以，我想像这样重写：

 (sum(c * e) over (partition by a and partition by rnc )) as sumProduct

Answer 1

我不确定您为什么要使用临时表，但您可以通过将它们包含在 partition by 列表中来按多列进行分区：

select *,
       (case when b like 'xf%' 
             then sum(c * e) over (partition by a, rnd )
        end) as sumProduct
into #testing3
from #testing2;