将 SUM 与其他列 SQL 组合到 select 中答案

【问题标题】：Insert SUM combine into select with other column SQL将 SUM 与其他列 SQL 组合到 select 中
【发布时间】：2017-05-27 15:20:04
【问题描述】：

我在 sql 中的 sum 函数有问题，如下所示：

SELECT Member.Name, Book.Title AS BookBought, Order_Member_Det.Quantity, Order_Member_Det.Price, Order_Member.Total
FROM Order_Member
INNER JOIN OrderWithMember ON Order_Member.OrderID = OrderWithMember.OrderID
INNER JOIN Order_Member_Det ON OrderWithMember.MemberOrderID = Order_Member_Det.MemberOrderID
INNER JOIN Member ON OrderWithMember.MemberID = Member.MemberID
INNER JOIN Book ON Order_Member_Det.BookID = Book.BookID

结果是：

Name    BookBought           Quantity Price Total
----------------------------------------------------
John    Flip it                 2     50    150
John    California Penal Code   1     50    150
Jack    Forum Internationale    2     80    160
Alice   Securitization          2     80    210
Alice   The Cervical Spine      1     50    210
Kevin   Trading Commodities     1     55    55
James   Aerodynamics            1     90    90

我想像这样使用 SUM(TOTAL) 来添加表中所有总数的 SUM：

SELECT Member.Name, Book.Title AS BookBought, Order_Member_Det.Quantity, Order_Member_Det.Price, Order_Member.Total, **SUM(Order_Member.Total)**
FROM Order_Member
INNER JOIN OrderWithMember ON Order_Member.OrderID = OrderWithMember.OrderID
INNER JOIN Order_Member_Det ON OrderWithMember.MemberOrderID = Order_Member_Det.MemberOrderID
INNER JOIN Member ON OrderWithMember.MemberID = Member.MemberID
INNER JOIN Book ON Order_Member_Det.BookID = Book.BookID

然后我得到一个错误：

消息 8120，第 16 级，状态 1，第 264 行
列“Member.Name”在选择列表中无效，因为它既不包含在聚合函数中，也不包含在 GROUP BY 子句中。

但是如果我像这样使用 sum 创建新的选择，它会起作用：

SELECT SUM(Total) From Order_Member;

它可以产生这个输出：

ColumnName
665

那么如何在给定的情况下组合两个选择，我也使用了 INNER JOIN 所以子查询可能在这里不起作用。有什么想法吗？

【问题讨论】：

"Msg 8120" 是 SQL Server 错误，而不是 MySQL 错误。我修复了标签，因为错误消息是正在使用的数据库的非常令人信服的证据。

标签： sql sql-server sum

【解决方案1】：

这应该也可以（未经测试）

with cte as
(
    SELECT Member.Name, Book.Title AS BookBought, 
        Order_Member_Det.Quantity, Order_Member_Det.Price, Order_Member.Total
    FROM Order_Member
    INNER JOIN OrderWithMember ON Order_Member.OrderID = OrderWithMember.OrderID
    INNER JOIN Order_Member_Det ON OrderWithMember.MemberOrderID = Order_Member_Det.MemberOrderID
    INNER JOIN Member ON OrderWithMember.MemberID = Member.MemberID
    INNER JOIN Book ON Order_Member_Det.BookID = Book.BookID
)
select *, (select sum(total) from cte) as SumTotal
from cte

【讨论】：

【解决方案2】：

在 SQL Server 中，您可以使用窗口函数来执行此操作：

SELECT m.Name, b.Title AS BookBought, omd.Quantity, omd.Price, om.Total,
       SUM(Order_Member.Total) OVER (PARTITION BY m.MemberId) as MemberTotal
FROM Order_Member om INNER JOIN
     OrderWithMember owm
     ON om.OrderID = owm.OrderID INNER JOIN
     Order_Member_Det omd
     ON owm.MemberOrderID = omd.MemberOrderID INNER JOIN
     Member m
     ON owm.MemberID = m.MemberID INNER JOIN
     Book b
     ON omd.BookID = b.BookID;

【讨论】：