【发布时间】:2021-08-23 19:33:25
【问题描述】:
我想获取每个 id 的每个状态的第一行。
每个状态可以有多行。所以我想根据之前的状态来获取每个状态的第一次出现。
例如info_required 首先出现在第 2 行,然后在第 4 行变为另一个状态 pending,然后在第 6 行再次变为 info_required。 同样,状态 pending 首先在第 4 行,然后在第 8 行,因为在第 4 行之后状态发生了变化,它需要在结果集中。
因此我想在下面获取第 1、2、4、6 和 8 行。
WITH t1 AS (
SELECT 1 AS row, 'A' AS id, 'created' AS status, '2021-05-18 18:30:00'::timestamp AS created_at UNION ALL
SELECT 2 AS row, 'A' AS id, 'info_required' AS status, '2021-05-19 11:30:00'::timestamp AS created_at UNION ALL
SELECT 3 AS row, 'A' AS id, 'info_required' AS status, '2021-05-19 12:00:00'::timestamp AS created_at UNION ALL
SELECT 4 AS row, 'A' AS id, 'pending' AS status, '2021-05-19 12:30:00'::timestamp AS created_at UNION ALL
SELECT 5 AS row, 'A' AS id, 'pending' AS status, '2021-05-20 13:30:00'::timestamp AS created_at UNION ALL
SELECT 6 AS row, 'A' AS id, 'info_required' AS status, '2021-05-20 14:30:00'::timestamp AS created_at UNION ALL
SELECT 7 AS row, 'A' AS id, 'info_required' AS status, '2021-05-20 15:30:00'::timestamp AS created_at UNION ALL
SELECT 8 AS row, 'A' AS id, 'pending' AS status, '2021-05-20 16:30:00'::timestamp AS created_at
)
SELECT *
FROM t1
【问题讨论】:
标签: sql snowflake-cloud-data-platform window-functions