如何将一个查询输出用于python中的另一个查询？

Question

我正在尝试将一个查询输出用于另一个。但没有得到正确的结果。你能帮我怎么做吗？

例子：

query1 = "select distinct lower(tablename) as tablename from medaff.imedical_metadata where object_type = 'View'"

上述查询的输出是：

tablename
vw_mdcl_insght
vw_fbms_interactions

我想在其他查询中使用上述输出。像这样-

query2 = "select * from medaff.imedical_business_metadata where objectname in ('vw_mdcl_insght', 'vw_fbms_interactions')"

这部分在python中怎么做？

我正在使用下面的代码来运行查询：

conn = redshift_conn()

with conn.cursor() as cur:
      query1 = "select distinct lower(tablename) as tablename from medaff.imedical_metadata where object_type = 'View'"
      cur.execute(sql_query)
      result = cur.fetchall()
      print(result)
      conn.commit()

      query2 = "select * from medaff.imedical_business_metadata where objectname in ('vw_mdcl_insght', 'vw_fbms_interactions')"
      cur.execute(sql_query)
      result = cur.fetchall()
      print(result)
      conn.commit()

Answer 1

我认为您可以使用in 查询：

select ibm.*
from medaff.imedical_business_metadata ibm
where ibm.objectname in (select lower(im.tablename) as tablename
                         from medaff.imedical_metadata im
                         where im.object_type = 'View'
                        );

最好让数据库来做。

Answer 2

我使用了以下代码：

query = "select distinct lower(tablename) from medaff.imedical_metadata where object_type = 'View'"
cur.execute(query)
res = cur.fetchall()
print(res)
res = tuple([item[0] for item in res])
res = str(res)