Oracle 表单个性化

Question

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我在表单个性化方面遇到问题，我是 oracle 的初学者 当用户访问最终就业表格并试图终止用户时，EBS 和 Forms.i 需要在 HR 模块中进行验证。 当最终用户单击 TERMINATE 按钮时，它应该检查条件，如果条件为空，那么它应该通过错误消息。

我正在使用这些条件

select 'Y'
from dual
where exists (select 'Y'
              from pa_expenditure_items_all paei,
                   pa_expenditures_all pae
              where paei.expenditure_id = pae.expenditure_id and
                    pae.incurred_by_person_id  = : person_id and
                    cost_distributed_flag = 'N'
             )

Answer 1

我猜应该是这样的：

declare
   l_yes  varchar2 (1);
begin
   select max ('Y')
     into l_yes
     from dual
    where exists
             (select 'Y'
                from pa_expenditure_items_all paei, pa_expenditures_all pae
               where     paei.expenditure_id = pae.expenditure_id
                     and pae.incurred_by_person_id = :person_id
                     and cost_distributed_flag = 'N');

   if l_yes is null
   then
      message ('Condition is not met');
      raise form_trigger_failure;
   else
      -- Do something; probably terminate that user
      null;
   end if;
end;

Answer 2

在“条件”字段中，您不要输入完整的查询。您只需放入一个布尔表达式（例如您将放入查询的WHERE 子句）。

所以，不如试试这个：

exists (select 'Y'
        from pa_expenditure_items_all paei,
             pa_expenditures_all pae
        where paei.expenditure_id = pae.expenditure_id and
              pae.incurred_by_person_id  = :person_id and
              cost_distributed_flag = 'N'
       )

:person_id 假定 PERSON_ID 是您的表单触发器触发的块中的一个字段。最好使用:block.field 形式使其更加明确。