Google Apps 脚本 setTimestamp 到 mysql 数据库

Question

我正在尝试创建一个谷歌应用程序脚本，该脚本采用 CSV 文件并将其推送到 mysql 数据库中。我无法插入日期和日期时间字段。 CSV 日期和日期时间字段的格式如下：2015-12-04 和 2015-12-04 20:02:14（如果包含时间）。我正在尝试在我的脚本中使用以下语句。 “日期”字段只有一个日期，没有时间，似乎它可能正在工作，所以问题可能是时间格式？：

var stmt = conn.prepareStatement('INSERT INTO product_detail('
      +'Invoice,Sales_ID,Product,Report_Category,Menu_Price,Sales,'
      +'Net_Sales,Gross_Sales,Sales_before_Discount_after_Taxes,Sales_after_Discount_after_Taxes,'
      +'Gratuity,GST,GST_Inc,PST,PST_Inc,Total_Sales_Taxes,Total_Item_Discounts,'
      +'Item_Discount_Name,Item_Discount_Employee,Total_Invoice_Discounts,Invoice_Discount_Name,'
      +'Invoice_Discount_Employee,Table,Date,Date_Opened,Date_Closed,Day,Day_of_week,Week,Month,'
      +'Year,Open_Station_ID,Open_Station,Closing_Station,Closing_Station_ID,Open_Employee,'
      +'Closing_Employee) VALUES ( (?, ?, ?, ?, ?, ?, ?, ?,'
      + '?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)');
  for (var i = 1; i < data.length; i++) {
    stmt.setString(1 ,data[i][0]);
    stmt.setString(2 ,data[i][1]);
    stmt.setString(3 ,data[i][2]);
    stmt.setString(4 ,data[i][3]);
    stmt.setString(5 ,data[i][4]);
    stmt.setString(6 ,data[i][5]);
    stmt.setString(7 ,data[i][6]);
    stmt.setString(8 ,data[i][7]);
    stmt.setString(9 ,data[i][8]);
    stmt.setString(10 ,data[i][9]);
    stmt.setString(11 ,data[i][10]);
    stmt.setString(12 ,data[i][11]);
    stmt.setString(13 ,data[i][12]);
    stmt.setString(14 ,data[i][13]);
    stmt.setString(15 ,data[i][14]);
    stmt.setString(16 ,data[i][15]);
    stmt.setString(17 ,data[i][16]);
    stmt.setString(18 ,data[i][17]);
    stmt.setString(19 ,data[i][18]);
    stmt.setString(20 ,data[i][19]);
    stmt.setString(21 ,data[i][20]);
    stmt.setString(22 ,data[i][21]);
    stmt.setString(23 ,data[i][22]);
    var date_insert = new Date(data[i][23]);
    var jdbc_timestamp = Jdbc.newTimestamp(date_insert.getTime());
    stmt.setTimestamp(24 ,jdbc_timestamp);
    date_insert = new Date(data[i][24]);
    jdbc_timestamp = Jdbc.newTimestamp(date_insert.getTime());
    stmt.setTimestamp(25 ,jdbc_timestamp);
    date_insert = new Date(data[i][25]);
    jdbc_timestamp = Jdbc.newTimestamp(date_insert.getTime());
    stmt.setTimestamp(26 ,jdbc_timestamp);
    stmt.setString(27 ,data[i][26]);
    stmt.setString(28 ,data[i][27]);
    date_insert = new Date(data[i][28]);
    jdbc_timestamp = Jdbc.newTimestamp(date_insert.getTime());
    stmt.setTimestamp(29 ,jdbc_timestamp);
    stmt.setString(30 ,data[i][29]);
    stmt.setString(31 ,data[i][30]);
    stmt.setString(32 ,data[i][31]);
    stmt.setString(33 ,data[i][32]);
    stmt.setString(34 ,data[i][33]);
    stmt.setString(35 ,data[i][34]);
    stmt.setString(36 ,data[i][35]);
    stmt.setString(37 ,data[i][36]);
    stmt.addBatch();
  }

Answer 1

getTime() 以毫秒为单位为您提供自 Unix 纪元以来的时间

如果您需要的是以某种方式格式化的时间戳字符串，则需要使用Utilities.formatDate(date, timeZone, format)。

示例：

  var timeZone = date_insert.getTimezoneOffset()
  var format = "yyyy-MM-dd HH:mm:ss"
  var formattedDate = Utilities.formatDate(date_insert, timeZone, format);