【发布时间】:2013-03-14 15:43:38
【问题描述】:
我需要编写一个连接数据库的java程序,程序应该提示用户输入7位数字ID,然后计算每个字母等级出现的次数和总等级数。
例如:学生 12345 一个:1 乙:0 C'S :3 D'S : 0 F'S: 哦 总成绩:4
我下面的代码工作正常,但问题是 no row 的结果不会给我 0 .. e.x :它只给我 A、C 并删除其他人
所以你知道如何在结果中显示 0。
谢谢你
import java.sql.*; // Use classes in java.sql package
import java.util.*;
public class DDBB {
public static void main (String args []) {
int a;
Scanner in = new Scanner(System.in);
System.out.println("Enter a 7 digit Number for StudentID");
a = in.nextInt();
System.out.println("StudentID" +" "+ a);
int countgrade ;
String GRADE1;
int totalcount;
Connection conn =null;
Statement st =null;
try {
DriverManager.registerDriver(new oracle.jdbc.driver.OracleDriver());
// Class.forName("oracle.jdbc.driver.OracleDriver");
String url ="jdbc:oracle:thin ....";
conn = DriverManager.getConnection(url,"user", "password");
// create a Statement object
PreparedStatement st1 = conn.prepareStatement(
"SELECT GRADE, Count(*) AS COUNT1 FROM GRADING WHERE StudentID = ? GROUP BY Grade ORDER BY GRADE");
st1.setInt(1, a);
ResultSet S = st1.executeQuery();
while (S.next()) {
countgrade = S.getInt("COUNT1");
GRADE1 = S.getString("GRADE");
System.out.println(GRADE1 + "'s :"+countgrade+"\n");
}
String Q2 ="SELECT COUNT(GRADE) AS COUNT2 FROM GRADING WHERE StudentID = ? ";
ResultSet S1 = st1.executeQuery(Q2);
while (S1.next()) {
totalcount = S1.getInt("COUNT2");
System.out.println("Total grades:"+ " " + totalcount+"\n");
}
S.close();
}
catch (SQLException e) {
e.printStackTrace();
}
finally {
try {
// close the Statement object using the close() method
if (st != null) {
st.close();
}
// close the Connection object using the close() method
if (conn != null) {
conn.close();
}
}
catch (SQLException e) {
e.printStackTrace();
}
}
}
}
【问题讨论】:
-
这需要一些格式化
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@MajidLAISSI 你现在可以看问题了吗?
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对我来说听起来像是一道作业题。
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@LuiggiMendoza 你告诉我 :)