【发布时间】:2017-02-23 19:35:28
【问题描述】:
public void create(String name) {
create_name = name;
try {
getConnection();
q = "create table ? (emp_id number (10), emp_name varchar (15))";
pst = con.prepareStatement(q);
pst.setString(1, create_name);
int j = pst.executeUpdate();
JOptionPane.showMessageDialog(new JDialog(), "Table is Created");
} catch (Exception e) {
JOptionPane.showMessageDialog(new JDialog(), "Table is not Created");
}
}
【问题讨论】:
-
您是否收到任何错误,您的表格是否已创建,您的问题究竟是什么?
-
您不能参数化对象标识符,如表名
标签: java sql oracle swing jdbc